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rosijanka [135]
2 years ago
12

A copper penny has a mass of 3.0 g. A total of 4.0 × 10^12 electrons are transferred from one neutral penny to another. If the e

lectrostatic force of attraction between the pennies is equal to the weight of a penny, what is the separation between them?
Physics
2 answers:
olga55 [171]2 years ago
7 0

Then the separation between the two pennies will be O.354m.

To find the correct answer, we need to know about the electrostatic force of attraction.

<h3>What is the separation between the pennies?</h3>
  • We have given with the information's,

                 m=3*10^{-3}kg\\n=4*10^{12}\\

  • As we know that the charge of one electron is 1.6×10^-19C.Thus, the total charge on the penny will be,

                 Q_1=4*10^{12}*1.6*10^{-19}=6.4*10^{-7}C.\\Q_2=-Q_1

  • We have the expression for electrostatic force of attraction as,

                    F_e=\frac{kQ_1Q_2}{r^2} =mg\\ , here given that the electrostatic force equal to the weight of the system.

  • We have to find the separation between the pennies.

                  r=\sqrt{\frac{kQ_1Q_2}{mg} } =\sqrt{\frac{(6.4*10^{-7})^2}{4*3.14*8.85*10^{-12}*3*10^{-3}*9.8} }\\\\r=0.354m

Thus, we can conclude that the separation between the pennies is 0.354m.

Learn more about the electrostatic force here:

brainly.com/question/28108740

#SPJ1

lbvjy [14]2 years ago
3 0

0.354m will be the separation between the two pennies.

We must understand the electrostatic force of attraction in order to arrive at the correct solution.

<h3>How far apart are the pennies from one another?</h3>
  • One electron has a charge of 1.6 10-19 coulombs, as is common knowledge. Consequently, the total fee for the penny will be,

                  Q_1=ne=4*10^{12}*1.67*10^{-19}=6.4*10^{-7}C\\Q_2=-Q_1

  • The expression of electrostatic force of attraction is as follows:

                      F=\frac{kQ_1Q_2}{R^2}=mg

Given that the electrostatic force in this instance is equal to the system's weight.

  • We must determine the distance between the pennies.

                    R=\sqrt{\frac{kQ_1Q_2}{mg} } =0.354m

As a result, we may say that the distance between the pennies is 0.354m.

Learn more about electrostatic force here:

brainly.com/question/28108740

#SPJ1

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