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olasank [31]
1 year ago
6

The table gives the populations of three countries in 2013.

Mathematics
1 answer:
natita [175]1 year ago
6 0

1) Difference of  the populations  of Germany and  Brazil = 1.16 X 10^8

2) Difference of  the populations  of Brazil and the  United States = 1.2 X 10^8

3) Sum of the  populations of  Brazil and  Germany = 2.76 X 10^8

4) Sum of the  populations of  the United States  and Brazil = 5.12 X 10^8

According to the statement

we have given that the populations of  three countries which are

United States is 3.16 × 10^8 and  Brazil is 1.96 × 10^8 and Germany is 8.0 × 10^7

And we have to arrange the sums and differences in increasing order of their values.

so, we have to find the

a) the difference of  the populations  of Germany and  Brazil

So,

Difference of  the populations  of Germany and  Brazil =  1.96 X 10^8 - 8 X 10^7 = 116000000 = 1.16 X 10^8

And then we have to find the

b) the sum of the  populations of  the United States  and Brazil

So,

Sum of the  populations of  the United States  and Brazil = 3.16 X 10^8 + 1.96 X 10^8 = 512000000 = 5.12 X 10^8

And then we have to find the

c) the difference of  the populations  of Brazil and the  United States

So,

Difference of  the populations  of Brazil and the  United States = 3.16 X 10^8 - 1.96 X 10^8 = 120000000 = 1.2 X 10^8

And then we have to find the

d) the sum of the  populations of  Brazil and  Germany

So,

Sum of the  populations of  Brazil and  Germany:  1.96 X 10^8 + 8 X 10^7 = 276000000 = 2.76 X 10^8

NOW, we arrange the sum and difference in increasing order of their values.

So,

1) Difference of  the populations  of Germany and  Brazil = 1.16 X 10^8

2) Difference of  the populations  of Brazil and the  United States = 1.2 X 10^8

3) Sum of the  populations of  Brazil and  Germany = 2.76 X 10^8

4) Sum of the  populations of  the United States  and Brazil = 5.12 X 10^8

Learn more about Addition here brainly.com/question/78672

#SPJ1

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\large\begin{array}{l}\\\\ \textsf{This question gives us a set}\\\\ \mathsf{S=\{n \in\mathbb{Z}:~1\le n\le 700\}}\\\\ \mathsf{S=\{1,\,2,\,3,\,\ldots,\,699,\,700\}}\\\\\\ \bullet~~\textsf{Set of integers that are divible by 2 (even integers):}\\\\ \mathsf{A=\{n\in \mathbb{Z}:~n=2k,\,k\in\mathbb{Z}\}}\\\\ \mathsf{A=\{\ldots,\,-4,\,-2,\,0,\,2,\,4,\,\ldots\}}\\\\\\ \bullet~~\textsf{Set of integers that are divible by 7:}\\\\ \mathsf{B=\{n\in \mathbb{Z}:~n=7k,\,k\in\mathbb{Z}\}}\\\\ \mathsf{A=\{\ldots,\,-14,\,-7,\,0,\,7,\,14,\,\ldots\}} \end{array}

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\large\begin{array}{l}\\\\ \textsf{We want to know how many elements there are in the}\\\textsf{following set:}\\\\ \mathsf{S\cap (A\cup B)=(S\cap A)\cup(S\cap B)\qquad(i)} \end{array}

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\large\begin{array}{l}\\\\ \bullet~~\mathsf{S\cap A=\{n\in\mathbb{N}:~n=2k~~and~~1\le n\le 700,\,k\in\mathbb{Z}\}}\\\\ \mathsf{S\cap A=\{2,\,4,\,6,\,\ldots,\,698,\,700\}}\\\\ \mathsf{S\cap A=\{1\cdot 2,\,2\cdot 2,\,3\cdot 2,\,\ldots,\,349\cdot 2,\,350\cdot 2\}}\\\\\\ \textsf{So, there are 350 elements in }\mathsf{S\cap A:}\\\\ \mathsf{\#(S\cap A)=350.} \\\\\\ \bullet~~\mathsf{S\cap B=\{n\in\mathbb{N}:~n=7k~~and~~1\le n\le 700,\,k\in\mathbb{Z}\}}\\\\ \mathsf{S\cap B=\{7,\,14,\,21,\,\ldots,\,693,\,700\}}\\\\ \mathsf{S\cap B=\{1\cdot 7,\,2\cdot 7,\,3\cdot 7,\,\ldots,\,99\cdot 7,\,100\cdot 7\}} \\\\\\ \textsf{So, there are 100 elements in }\mathsf{S\cap B:}\\\\ \mathsf{\#(S\cap B)=100.} \end{array}

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\large\begin{array}{l}\\\\ \textsf{Therefore,}\\\\ \mathsf{\#\big[S\cap (A\cup B)\big]}\\\\ =\mathsf{\#\big[(S\cap A)\cup(S\cap B)\big]}\\\\ =\mathsf{\#(S\cap A)+\#(S\cap B)-\#\big[(S\cap A)\cap(S\cap B)\big]}\\\\ =\mathsf{350+100-50}\\\\ =\mathsf{450-50}\\\\ =\mathsf{400~elements.}\\\\\\ \textsf{There are 400 integers in S that are divisible by 2 or 7.} \end{array}


If you're having problems understanding the answer, try to see it through your browser: brainly.com/question/2105863


\large\begin{array}{l}\\\\ \textsf{Any doubts? Please, comment below.}\\\\\\ \textsf{Best wishes! :-)} \end{array}


Tags: <em>set theory divibilility divisible integers union intersection</em>

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