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agasfer [191]
2 years ago
7

Which sample contains the largest number of oxygen atoms? Select one: a. 8.0 g of carbon dioxide b. 8.0 g of potassium chlorate

c. 8.0 g of calcium perchlorate d. 8.0 g of sodium hydroxide
Chemistry
1 answer:
adell [148]2 years ago
5 0

The sample with the largest number of oxygen atoms will be calcium perchlorate.

<h3>Number of atoms in a compound</h3>

Since we are not looking at the number of moles, the mass of the compounds has no bearing on the number of atoms of oxygen.

  • The chemical formula for carbon dioxide is CO_2. Thus, it has 2 atoms of oxygen.
  • The chemical formula for potassium chlorate is KClO_3. Thus, it has 3 oxygen atoms.
  • The chemical formula for calcium perchlorate is Ca(ClO_4)_2. Thus, it has 8 atoms of oxygen.
  • The chemical formula for sodium hydroxide is NaOH. Thus, it has 1 atom of oxygen.

Therefore, the compound with the largest number of oxygen atoms is calcium perchlorate.

More on the number of atoms in compounds can be found here: brainly.com/question/1686912

#SPJ1

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Rank the following elements by effective nuclear charge, Zeff, for a valence electron. F LI Be B N
Stels [109]

Answer:

Rank in increasing order of effective nuclear charge:

  • Li < Be < B < N < F

Explanation:

This explains the meaning of effective nuclear charge, Zeff, how to determine it, and the calculations for a valence electron of each of the five given elements: F, Li, Be, B, and N.

<u>1) Effective nuclear charge definitions</u>

  • While the total positive charge of the atom nucleus (Z) is equal to the number of protons, the electrons farther away from the nucleus experience an effective nuclear charge (Zeff) less than the total nuclear charge, due to the fact that electrons in between the nucleus and the outer electrons partially cancel the atraction from the nucleus.

  • Such effect on on a valence electron is estimated as the atomic number less the number of electrons closer to the nucleus than the electron whose effective nuclear charge is being determined: Zeff = Z - S.

<u><em>2) Z eff for a F valence electron:</em></u>

  • F's atomic number: Z = 9
  • Total number of electrons: 9 (same numer of protons)
  • Period: 17 (search in the periodic table or do the electron configuration)
  • Number of valence electrons:  7 (equal to the last digit of the period's number)
  • Number of electrons closer to the nucleus than a valence electron: S = 9 - 7 = 2
  • Zeff = Z - S = 9 - 2 = 7

<u><em>3) Z eff for a Li valence eletron:</em></u>

  • Li's atomic number: Z = 3
  • Total number of electrons: 3 (same number of protons)
  • Period: 1 (search on the periodic table or do the electron configuration)
  • Number of valence electrons: 1 (equal to the last digit of the period's number)
  • Number of electrons closer to the nucleus than a valence electron: S = 3 - 1 = 2
  • Z eff = Z - S = 3 - 2 = 1.

<em>4) Z eff for a Be valence eletron:</em>

  • Be's atomic number: Z = 4
  • Total number of electrons: 4 (same number of protons)
  • Period: 2 (search on the periodic table or do the electron configuration)
  • Number of valence electrons: 2 (equal to the last digit of the period's number)
  • Number of electrons closer to the nucleus than a valence electron: S = 4 - 2 = 2
  • Z eff = Z - S = 4 - 2 = 2

<u><em>5) Z eff for a B valence eletron:</em></u>

  • B's atomic number: Z = 5
  • Total number of electrons: 5 (same number of protons)
  • Period: 13 (search on the periodic table or do the electron configuration)
  • Number of valence electrons: 3 (equal to the last digit of the period's number)
  • Number of electrons closer to the nucleus than a valence electron: S = 5 - 3 = 2
  • Z eff = Z - S = 5 - 2 = 3

<u><em>6) Z eff for a N valence eletron:</em></u>

  • N's atomic number: Z = 7
  • Total number of electrons: 7 (same number of protons)
  • Period: 15 (search on the periodic table or do the electron configuration)
  • Number of valence electrons: 5 (equal to the last digit of the period's number)
  • Number of electrons closer to the nucleus than a valence electron: S = 7 - 5 = 2
  • Z eff = Z - S = 7 - 2 = 5

<u><em>7) Summary (order):</em></u>

  Atom          Zeff for a valence electron

  • F                   7
  • Li                   1
  • Be                 2
  • B                   3
  • N                   5

  • <u>Conclusion</u>: the order is Li < Be < B < N < F
6 0
3 years ago
A warm ocean transfers heat to the air above it. Which type of heat transfer is this
Zigmanuir [339]

Answer:

Conduction

Explanation:

Because When air is  in contact with the ocean it is at a different temperature than the seas surface

7 0
3 years ago
Read 2 more answers
What is the mass, in grams, of 1.4 mol W
algol [13]
Atomic mass W = 183.84 u.m.a

1 mole --------- 183.84
1.4 moles ---- ?

1.4 x 183.84 / 1 = 257.376 g

hope this helps!
3 0
3 years ago
How many carbon atoms are there in .500 mol of CO2?
AURORKA [14]

Answer: There are 3.011 \times 10^{23} atoms present in 0.500 mol of CO_{2}.

Explanation:

According to the mole concept, there are 6.022 \times 10^{23} atoms present in 1 mole of a substance.

In a molecule of CO_{2} there is only one carbon atom present. Therefore, number of carbon atoms present in 0.500 mol of CO_{2} are as follows.

1 \times 0.500 \times 6.022 \times 10^{23}\\= 3.011 \times 10^{23}

Thus, we can conclude that there are 3.011 \times 10^{23} atoms present in 0.500 mol of CO_{2}.

6 0
2 years ago
Which of the following is an example of anaerobic respiration?
Andrews [41]
Respiring while swimming underwater
Because anaerobic respiration means respiration with no oxygen, and there is no oxygen underwater
8 0
3 years ago
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