You need 0.111 g of NH₃ to provide the same number of molecules as
in 0.95 g of SF₆.
<em>Step 1</em>. Convert grams of SF₆ to moles of SF₆
Moles of SF₆ = 0.95 g SF₆ × (1 mol SF₆/146.06 g SF₆) = 0.006 50 mol SF₆
Now, we can use the knowledge that <em>1 mol of anything has the same number of molecules</em> (Avogadro’s number) <em>as 1 mol of anything else</em>
.
Thus, 0.006 50 mol NH₃ has the same number of molecules
as 0.006 50 mol SF₆.
<em>Step 2</em>. Convert moles of NH₃ to grams of NH₃.
Mass of NH₃ = 0.006 50 mol NH₃ × (17.03 g NH₃/1 mol NH₃) = 0.111 g NH₃
Answer: I think it could be Decomposition
Explanation: I think is composition because decomposition starts by being together and ends up as two
Physical changes are used to separate mixtures into their component compounds, but can not usually be used to separate compounds into chemical elements or simpler compounds.Physical changes occur when objects or substances undergo achange that does not change their chemical composition.