<span>Molten barium
chloride is separetes:</span><span>
BaCl</span>₂(l) →
Ba(l) + Cl₂(g), <span>
but first ionic bonds in this salt are separeted
because of heat:
BaCl</span>₂(l) →
Ba²⁺(l) + 2Cl⁻(l).
Reaction of reduction
at cathode(-): Ba²⁺(l) + 2e⁻ → Ba(l).
Reaction of oxidation
at anode(+): 2Cl⁻(l) → Cl₂(g) + 2e⁻.
The anode is positive
and the cathode is negative.
Answer:
D) 2 NOCl(g) ⇄ 2 NO(g) + Cl₂(g); Kp = 1.7 × 10⁻²
Explanation:
In order to compare the degree of decomposition of these reactions, we have to compare the equilibrium constant Kp. Kp is equal to the partial pressure of the products raised to their stoichiometric coefficients divided by the partial pressure of the reactants raised to their stoichiometric coefficients. The higher the Kp, the more products and fewer reactants at equilibrium. Among these reactions, D is the one that has the highest Kp, therefore the one experiencing the largest degree of decomposition.
Answer:
2
Explanation:
cause it is what it is :> mark me brainlest
Ca(OH)2 because Calcium tends to favor a positive 2 charge and OH tensd to favor a negative 1 charge.
Liquids flow and take the shape of their containers.
