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kogti [31]
3 years ago
12

Part One: Calculate the molarity of Ba2+ in an aqueous solution that contains 1.7 g of Ba(OH)2 in 0.75 L of solution.

Chemistry
1 answer:
denpristay [2]3 years ago
3 0

Explanation:

Ba(OH)2 ==>  Ba2+  +  2OH-

1.7 g = 0.008172796 moles Ba(OH)_2

1:1 for Ba2+ = 0.008172796 moles / .15L = 0.054M

2:1 for OH- = 0.016345593 moles / .15L = 0.109M

Kw = [H+] x [OH-] = 10^{-14}

10^{-14} / 0.109 = 9.2×10^{-14}  = [H+]

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