Answer:
The answers are in the explanation
Explanation:
For the equilibrium:
B(aq) + H₂O(l) ⇌ HB⁺(aq) + OH⁻(aq).
By LeChatelier's principle, the increase in the concentration of a reactant (for example) at equilibrium will change the system counteracting the increasing producing more product.
Thus,
A) Will the equilibrium constant for the reaction increase, decrease, or stay the same? Why?
.
The equilibrium constant is a thermodynamic constant that stay the same with the addition of a compound.
B) Will the concentration of HB⁺(aq) increase, decrease, or stay the same? Why?
By LeChatelier's principle, the addition of B will induce the formation of more HB⁺(aq) increasing the concentration.
C) Will the pH of the solution increase, decrease, or stay the same? Why?
As the addition of B induce the increasing of OH⁻, the pH of the solution will increase.
I hope it helps!
Average distance between gas molecules become double,, hope it helpss
Answer:
Biotic factor
Explanation:
Competition only exist due to limited resources (abiotic factors AKA environment) which occurs in biotic factors (living organisms).
Fear factor is nonsense because fear does not exist in plants but they still compete for sunlight and water.
Factory factor is nonsense as well because this term does not exist in biology.
The correct answer is false. Not only one type of balance is present in a laboratory. Most laboratory I've worked into owns two types of balance namely the analytical balance and the top-loading balance. The former is used for accurate mass readings and those needs smaller amounts of a substance while the latter is used for approximation and large amounts of substances.
Answer:
85.6 g
Explanation:
Step 1: Write the balanced combustion equation
C₃H₈ + 5 O₂ ⇒ 3 CO₂ + 4 H₂O
Step 2: Calculate the moles corresponding to 140 g of H₂O
The molar mass of H₂O is 18.02 g/mol.
140 g × 1 mol/18.02 g = 7.77 mol
Step 3: Calculate the moles of C₃H₈ needed to produce 7.77 moles of H₂O
The molar ratio of C₃H₈ to H₂O is 1:4. The moles of C₃H₈ needed are 1/4 × 7.77 mol = 1.94 mol.
Step 4: Calculate the mass corresponding to 1.94 moles of C₃H₈
The molar mass of C₃H₈ is 44.10 g/mol.
1.94 mol × 44.10 g/mol = 85.6 g