Answer:
0.0626 M
Explanation:
Equation of the reaction
CH3COOH(aq) + NaOH(aq) ---------> CH3COONa(aq) + H2O
Concentration of acid CA= ???
Concentration of base CB= 0.1943 M
Volume of acid VA= 10.0ml
Volume of base VB= 32.22 ml
Number of moles of acid NA= 1
Number of moles of base NB= 1
From
CA= CB VB NA/VA NB
Hence ;
CA= 0.1943 M × 32.22 ml × 1/10.0ml ×1
CA= 0.0626 M
Living organisms contain relatively large amounts of oxygen, carbon, hydrogen, nitrogen, and sulfur (thesefive elements are known as the bulk elements), along with sodium, magnesium, potassium, calcium, chlorine, and phosphorus (these six elements are known as macrominerals).
The heat is involved in the production of 5.0 mol of MgO is 180 Kj
calculation
2 Mg (s) +O2 → 2 MgO
From the equation above two moles of MgO is used therefore
72.3 is for 2 moles
that is 72.3 kj = 2moles
? = 5 moles
by cross multiplication
= 72.3 kj × 5/2 = 180 Kj
The atomic radii of the atoms in the group 1 increases down the group as we go from Hydrogen to Francium.
<h3>What is atomic radii ?</h3>
The total distance from the nucleus of an atom to the outermost orbital of its electron is known as its atomic radii or atomic radius.
As we go down the group, the number of orbits or shell increases.
Hence, atomic radii of the atoms in the group 1 increases down the group as we go from Hydrogen to Francium.
Learn more about atomic radii here ;
brainly.com/question/14086621
#SPJ1
(aq) +
(aq) ⇒
The sum of total charges of the reactant = 3×(2+) + 2×(3-)
= 6 + (-6)
=0
