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2 years ago

A What is the functional group of propanal?

Chemistry

2 answers:

sashaice [31]2 years ago

8 0

Answer:

(C 2 H 5 CHO) the functional present proposal of this is CHO

(aldehyde group). concept nomenclature of organic compounds (UIPAC)

Harlamova29_29 [7]2 years ago

4 0

Answer:

Explanation:

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Which is an element hydrogen , air , carbon dioxide , water

Basile [38]

Answer:

Hydrogen is an element

Explanation:

Hydrogen is an element with only hydrogen atoms, whereas air, carbon dioxide, and water are all made up of multiple elements with different types of atoms.

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3 years ago

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How many atoms of group 17 element would be needed react with one atom of a group 2 element? Explain

shusha [124]

Only one atom because atom with 17 electrons need that one electron to become stable

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2 years ago

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Which of the following is the correct name for the compound HF? Hydrogen floride hydrogen monofloride Hydroflorous acid Hydroflo

Nataliya [291]

Answer: The correct answer is Hydrogen Fluoride.

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2 years ago

Suppose a 2.95 g of potassium iodide is dissolved in 350. mL of a 62.0 m M aqueous solution of silver nitrate. Calculate the fin

STALIN [3.7K]

Answer : The final molarity of iodide anion in the solution is 0.0508 M.

Explanation :

First we have to calculate the moles of $KI$ and $AgNO_3$ .

$\text{Moles of }KI=\frac{\text{Mass of }KI}{\text{Molar mass of }KI}$

Molar mass of KI = 166 g/mole

$\text{Moles of }KI=\frac{2.95g}{166g/mole}=0.0178mole$

and,

$\text{Moles of }AgNO_3=\text{Concentration of }AgNO_3\times \text{Volume of solution}=0.0620M\times 0.350L=0.0217mole$

Now we have to calculate the limiting and excess reagent.

The given chemical reaction is:

$KI+AgNO_3\rightarrow KNO_3+AgI$

From the balanced reaction we conclude that

As, 1 mole of KI react with 1 mole of $AgNO_3$

So, 0.0178 mole of KI react with 0.0178 mole of $AgNO_3$

From this we conclude that, $AgNO_3$ is an excess reagent because the given moles are greater than the required moles and KI is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of $AgI$

From the reaction, we conclude that

As, 1 mole of $KI$ react to give 1 mole of $AgI$

So, 0.0178 moles of $KI$ react to give 0.0178 moles of $AgI$

Thus,

Moles of AgI = Moles of $I^-$ anion = Moles of $Ag^+$ cation = 0.0178 moles

Now we have to calculate the molarity of iodide anion in the solution.

$\text{Concentration of }AgNO_3=\frac{\text{Moles of }AgNO_3}{\text{Volume of solution}}$

$\text{Concentration of }AgNO_3=\frac{0.0178mol}{0.350L}=0.0508M$

Therefore, the final molarity of iodide anion in the solution is 0.0508 M.

3 0

2 years ago

Why is the chemistry of actinoids complicated?

gladu [14]

Answer:

Explanation:

Actinoids are the series have 15 element in the periodic table.

Chemistry of actinoids are complicated because of the following reasons.

Their outer most orbitals are 6d and 7s but most of the electrons resides in 5f orbitals. These orbitals are most exposed to environment and incoming electron picked up by 5f orbital instead of 6d or 7s orbitals.
They are radioactive elements that couldn't be handle in normal condition to study their properties.
Their f-orbital can accommodate 14 electrons and they have many variable oxidation state.
5d electron donot contribute in the formation of chemical bonds.
They have a very strong tendency to make complexes
Most of the actinoides are artificial and are in very minute in amount. they are in very less quantity that is amounts found in nano-grams so are more expensive too and
As they are radioactive so their half life is very short and in very less time the decay occur so couldn't be study as upon decay their actual properties changed.

Due to all the above reasons it make difficult for a chemist to study about the chemical properties of actinoids.

8 0

3 years ago