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iris [78.8K]
2 years ago
11

What is the radian measure of central angle AOB in the circles? Write down the answer in the lowest terms

Mathematics
1 answer:
Katena32 [7]2 years ago
5 0

5pi/12 radians

The arc measure is 75, so theta must also be the same. if theta is 75, and 75 in radians is 5pi/12 radians, then the answer is that.

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43, 47, is the composite numbers between 41 and 50
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Use the associative property to write am expression equivalent to (n+3) +4
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D is the correct answer.

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The cost of renting a game at the video store can be described by the function y=5x+4
topjm [15]

Answer:

2 days

Step-by-step explanation:

Use the given formula

y = 5x + 4

The information:

y is the money spent

x is the number of days

It is known that Justin spent $18

so now just substitute in that value

$18 = 5x + 4

and simplfiy by inverse operations

18 = 5x + 4

-4        -4

14 = 5x

/5    /5

2.8 = x

As per this problem, one can infer that renting a game is done by days, and will be charged in days, hence renting a game for 0.8 days is pointless

meaning that the final answer is 2 full days

6 0
3 years ago
What is 50 + 9 - 6 equals
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Answer:

53

Step-by-step explanation:

3 0
2 years ago
Read 2 more answers
A warehouse distributor of carpet faces a normally distributed demand for its carpet. The average demand for carpet from the sto
Snezhnost [94]

Answer with Step-by-step explanation:

Since the demand is normally distributed the required probability can be found from the area under the normal distribution curve as

Part a)

Given mean = 4500 yards per month

Standard deviation = 900 yards

Thus area under the curve corresponding to 6000 yards is found from the standard variate factor Z as

Z=\frac{X-\bar{X}}{\sigma }\\\\Z=\frac{6000-4500}{900}=1.67

Area for Z = 1.67 = 95.22%

Thus the probability that the demand will be met is 0.9522 hence the probability that the demand will not be met is P(E)=1-0.9522=0.0478

Part b)

The reuired answer is area between 5000 and 7000 yards in the normal distribution curve thus we have

Z_1=\frac{5000-4500}{900}=0.56.

Z_2=\frac{7000-4500}{900}=2.78

The area between these 2 values is 49.73% hence the reuired probability is 0.4973.

Part c)

For 97% satisfaction of demand the Z factor corresponding to 97% of area is found to be 1.88

thus we can write

1.88=\frac{X-4500}{900}\\\\X=4500+1.88\times 1.88=6193

4 0
3 years ago
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