Answer:
![y=3x+1](https://tex.z-dn.net/?f=y%3D3x%2B1)
Step-by-step explanation:
The line has positive slope, therefore the variable in the equation must be positive (
and
must be discarded)
Now, in the graph we can see that the line passes over the following points:
![(0,1) \rightarrow x=0, y=1\\(1,4) \rightarrow x=1, y=4](https://tex.z-dn.net/?f=%280%2C1%29%20%5Crightarrow%20x%3D0%2C%20y%3D1%5C%5C%281%2C4%29%20%5Crightarrow%20x%3D1%2C%20y%3D4)
With the point
, we can discard
because:
in the equation
, we have: ![x=0 \rightarrow y=3(0)-1=0-1=-1\rightarrow y=-1](https://tex.z-dn.net/?f=x%3D0%20%5Crightarrow%20y%3D3%280%29-1%3D0-1%3D-1%5Crightarrow%20y%3D-1)
The line doesn't pass over the point ![(0,-1)](https://tex.z-dn.net/?f=%280%2C-1%29)
Therefore, the equation is
.
We can verify the answer with the points
and
, replacing values in the equation:
![(0,1):\\x=0\rightarrow y=3(0)+1=0+1=1\rightarrow y=1\\\\(1,4):\\x=1\rightarrow y=3(1)+1=3+1=4\rightarrow y=4](https://tex.z-dn.net/?f=%280%2C1%29%3A%5C%5Cx%3D0%5Crightarrow%20y%3D3%280%29%2B1%3D0%2B1%3D1%5Crightarrow%20y%3D1%5C%5C%5C%5C%281%2C4%29%3A%5C%5Cx%3D1%5Crightarrow%20y%3D3%281%29%2B1%3D3%2B1%3D4%5Crightarrow%20y%3D4)