Solube is able to dissolve to certain extent usually in reference to water
7.2/4.0=1.8 then, 4.0=7.2/1.8
Answer:
(e) -6.1 J/K
Explanation:
Step 1: Given data
- Heat of fusion of ice (ΔH°fus): 333.5 J/g
Step 2: Calculate the heat (Qfreezing) required to freeze 5.0 g of water
We will use the following expression.
Qfreezing = -ΔH°fus × m
Qfreezing = -333.5 J/g × 5.0 g = -1.7 × 10³ J
Step 3: Calculate the entropy change (ΔS°) at 0 °C (273.15 K) and 1 atm
We will use the following expression.
ΔS° = Qfreezing/T
ΔS° = -1.7 × 10³ J/273.15 K = -6.1 J/K
