Sample left = 6.25 g
The percentage = 6.25%
<h3>Further explanation</h3>
Given
t1/2 = half-life = 3.8 days
t = decay time = 15.2 days
No = initial sample = 100 g
Required
Nt = final sample left
The percentage
Solution
General formulas used in decay:
Input the value :
The percentage : Nt/No
6.25 : 100 = 6.25%
Answer:
The molar heat of vaporization of dichloromethane is 30.8kJ/mole
Explanation:
Using Clausius Clapeyron equation
ln (P1/P2) = (ΔHvap/R) (1/T2-1/T1)
At initial temperature of Ooc , the vapour pressure is 134mmHg
Therefore T1 = 0+273 =273K
And P1 = 134mmHg
At normal boiling point of 40oC , the vapour pressure is 760mmhg
T2 = 40 +273 = 313K
P2 = 760mmHg
ln (134/760) = ΔHvap/(8.3145 J/molK)
( 1/313K - 1/273K)
ΔHvap = 30800J/mol
= 30.8kJ/mol
Therefore, the molar heat of vaporization can be calculated using
Clausius Clapeyron equation using the above steps
Based on the available facts, in the northeast United States, the biggest source of acid rain producing pollutants comes from the burning of coal by power plants to produce electricity.
<h3>What is acid rain?</h3>
Acid rain occurs when gases such as sulfur (iv) oxide and nitrogen oxides which are released from the burning of fossil fuels such as petrol and coal are released into the atmosphere, which then dissolve in rainwater and fall as acid rain.
These gases are known as acid anhydrides because they dissolve in water to produce acids.
In the northeast United States, the biggest source of acid rain producing pollutants comes from the burning of coal by power plants to produce electricity.
Learn more about acid rain at: brainly.com/question/718250
Answer:
T = 42.08 °C
Explanation:
Using the expression,
Wherem
is the activation energy
R is Gas constant having value = 8.314 J / K mol
Thus, given that, = 45.6 kJ/mol = 45600 J/mol (As 1 kJ = 1000 J)
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T = (30 + 273.15) K = 303.15 K
So,
Conversion to °C as:
T(K) = T( °C) + 273.15
So,
315.23 = T( °C) + 273.15
<u>T = 42.08 °C</u>
