The rate of the reaction defines by the slowest stage. So the rate of the reaction is <span>d. rate = k[b]^2[c].</span>
Answer:
A.) 2.0 M
Explanation:
Molarity=mole of solutes/Liters of solution so M=mol/L
2moles/4 L =2 M
First is to calculate the mass of required for the 0.50 M ammonium carbonate. assuming ammonium carbonate is 100 % pure
m = 0.5 L ( 0.50 mol ammonium carbonate / L) ( 96.09 g ammonium carbonate/ mol ammonium carbonate)
m = 24.0225 g ammonium carbonate
1. weigh 24.0225 g ammonium carbonate
2. place it in a 500-ml volumetric flask
3. add water to volumetric flask up to the line.
4. placed the cap and then shake properly.
Answer:
The answer to your question is: Cp = 350.4 J/ kg°C
Explanation:
Data
mass = m = 4.7 g convert grams to kilograms 0.0047 kg
heat= Q = 52.7 J
Temperature = 25 - 57 °C
Formula
Q = mCpΔT solve for Cp
Cp = Q / mΔT
Process
Cp = 52.7 / [(0.0047)(57 - 25)] Substitution
Cp = 52.7 / 0.1504
Cp = 350.4 J/ kg°C