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ch4aika [34]
3 years ago
9

On the calendar, the full moon is shown happening on the eleventh of the month. What moon would you see around the date shown wi

th the question mark?
First Quarter

New Moon

Waxing Crescent

Waning Gibbous
Chemistry
1 answer:
Elan Coil [88]3 years ago
7 0

Answer: waning gibbous

Explanation:

Your welcome

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List the official SI units
Juli2301 [7.4K]

Answer:

The seven SI base units, which are comprised of:

Length - meter (m)

Time - second (s)

Amount of substance - mole (mole)

Electric current - ampere (A)

Temperature - kelvin (K)

Luminous intensity - candela (cd)

Mass - kilogram (kg)

Explanation:

7 0
3 years ago
Read 2 more answers
A student measures the mass of a sample as 9.64 g. Calculate the percentage error, given that the correct mass is 9.80 g.
rosijanka [135]

Answer:

<h3>The answer is 1.63 %</h3>

Explanation:

The percentage error of a certain measurement can be found by using the formula

P(\%) =  \frac{error}{actual \:  \: number}  \times 100\% \\

From the question

actual mass = 9.80 g

error = 9.80 - 9.64 = 0.16

We have

p(\%) =  \frac{0.16}{9.80}  \times 100 \\  = 1.632653061...

We have the final answer as

<h3>1.63 %</h3>

Hope this helps you

5 0
3 years ago
What is the hybridization and shape for an XeF6 2+ molecule?
Anna11 [10]

Answer:

Xe:[Kr]4d¹⁰5(sp³d³)₆⁺² => Octahedral Geometry (AX₆)⁺²

Explanation:

Xe:[Kr]4d¹⁰(5s²5p₋₁²p₀²p₁²5d₋₂d₋₁d₀)⁺² => Xe[Kr]5(sp³d³)₆²

Ca. #Valence e⁻ = Xe + 6F - 2e⁻ = 1(8) + 6(7) - 2 = 48

Ca. #Substrate e⁻ = 6F = 6(8) = 48

#Nonbonded free pairs e⁻ = (V - S)/2 = (48 - 48)/2 = 0 free pairs

#Bonded pairs e⁻ = 6F substrates = 6 bonded pairs

BPr + NBPr = 6 + 0 = 6 e⁻ pairs => Geometry => [AX₆]⁺² => Octahedron

Xe:[Kr]4d¹⁰(5s²5p₋₁²p₀²p₁²5d₋₂d₋₁d₀)⁺² => Xe[Kr]5(sp³d³)₆⁺²    

XeF₆⁺² => 6(sp³d³) hybrid orbitals => Octahedral Geometry (AX₆)      

8 0
2 years ago
How many moles of CO2 are there in 8.91 x 1023 molecules of CO2?<br> (1 mole= 6.02 x 1023)
Karo-lina-s [1.5K]

Answer:

<h2>1.48 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{8.91 \times  {10}^{23} }{6.02 \times  {10}^{23} }  =  \frac{8.91}{6.02}  \\  = 1.480066...

We have the final answer as

<h3>1.48 moles</h3>

Hope this helps you

6 0
3 years ago
Explain the energy transformation that occurs when food is digested.
Lunna [17]

<em>Answer:</em>

<em>C. Mechanical energy transforms into chemical energy.</em>

<em>Explanation:</em>

<em>Mechanical energy is used to chew the food, which is made up of chemical bonds. When we chew, those bonds break, releasing chemical energy that we utilize and consume.</em>

<em>Hope this helped. Have a nice day.</em>

4 0
2 years ago
Read 2 more answers
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