Answer:
<u>= 2.2 g pf S. produced</u>
Explanation:
Balanced Reaction equation:
→ 
1 mole of H2S - 34.1g
? moles - 3.2g
= 3.2/34.1 =<u> 0.09 moles of H2S</u>
Also,
1 mole of S02 - 64.07 g
? moles - 4.42g
= 4.42/64.07 <u>= 0.069 moles of SO2</u>
<u />
<em>Meaning SO2 is the limiting reagent</em>
Finally, 3 moles of S - 32g of sulphur
0.069 mole = ? g of Sulphur
= 0.069 x 32
<u>= 2.2 g pf S.</u>
Answer:
c
Explanation:
use %composition given to calculate emperical 4mular
Answer: 97.2223 ml
Explanation:
The rule that we will use to solve this problem is:
M2*V1 = M2*V2 where:
M1 is the initial concentration = 3.5 m
V1 is the initial volume = 0.25 l = 250 ml
M2 is the final concentration = 9 m
V2 is the final volume that we need to find
Substitute with the givens in the above equation to get V2 as follows:
3.5*250 = 9*V2
V2 = <em><u>97.2223 ml</u></em>
