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omeli [17]
2 years ago
13

Question 7

Chemistry
1 answer:
icang [17]2 years ago
4 0

Answer:

D.) The attraction between the delocalized electrons and the metal's cations

Explanation:

Metallic bonds form between free-floating valence electrons (delocalized electrons) and positively charged metal ions (cations). The negative charge from the electrons and the positive charge from the ions are what form the attraction.

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According to the big bang theory, which statement is accurate about how the universe came to be?
DIA [1.3K]

Answer:

The term Big Bang defines that the Universe has expanded from the ancient hot and thick primary situation at some fixed time in the past.

Big Bang theory refers to the origin of the Universe. In the beginning, universe is very heavy and small hot ball of matter. It was a point no bigger than the head of a pin when all the things squished with each other and universe is expanded with huge explosion of energy. Due to expansion, it is cooled and results in the formation of Stars and galaxies. After sometime, atoms formed like helium and hydrogen.

Thus, statement (1), (3) and (4) is correct whereas statement (2) and (5) is incorrect. the right answer is - (It expanded slowly), (Stars and galaxies formed,) (Atoms such as hydrogen and helium formed.)

Explanation:

8 0
3 years ago
Read 2 more answers
Why are red blood cells red
KonstantinChe [14]

Red blood cells are red because they contain Haemoglobin

8 0
3 years ago
A student prepared a stock solution by dissolving 20.0 g of NaOH in enough water to make 150. mL of solution. She then took 15.0
pav-90 [236]

Answer:

0.769\ \text{M}

Explanation:

Mass of stock solution = 20 g

Molar mass of NaOH = 40 g/mol

Volume of stock solution = 0.150 mL

M_2 = Concentration of NaOH for the final solution

V_1 = Amount of stock solution taken = 15 mL

V_2 = Total volume of solution = 65 mL

Molarity is given by

M_1=\dfrac{\text{Mass}}{\text{Molar mass}\times \text{Volume}}\\\Rightarrow M_1=\dfrac{20}{40\times 0.15}\\\Rightarrow M_1=\dfrac{10}{3}

We have the relation

M_1V_1=M_2V_2\\\Rightarrow M_2=\dfrac{M_1V_1}{V_2}\\\Rightarrow M_2=\dfrac{\dfrac{10}{3}\times 15}{65}\\\Rightarrow M_2=0.769\ \text{M}

The concentration of NaOH for the final solution is 0.769\ \text{M}.

5 0
3 years ago
Consider the reaction:
stich3 [128]

Answer:

\large \boxed{\text{-851.4 kJ/mol}}

Explanation:

2Al(s) + Fe₂O₃(s) ⟶ Al₂O₃(s) + 2Fe(s); ΔᵣH = ?

The formula for calculating the enthalpy change of a reaction by using the enthalpies of formation of reactants and products is

\Delta_{\text{r}}H^{\circ} = \sum \Delta_{\text{f}} H^{\circ} (\text{products}) - \sum\Delta_{\text{f}}H^{\circ} (\text{reactants})

                            2Al(s) + Fe₂O₃(s) ⟶ Al₂O₃(s) + 2Fe(s)

ΔfH°/kJ·mol⁻¹:         0         -824.3         -1675.7         0

\begin{array}{rcl}\Delta_{\text{r}}H^{\circ} & = & [1(-1675.7) + 2(0)] - [2(0) - 1(-824.3)]\\& = & -1675.7 + 824.3\\& = & \textbf{-851.4 kJ/mol}\\\end{array}\\\text{The enthalpy change is } \large \boxed{\textbf{-851.4 kJ/mol}}

7 0
4 years ago
Word equation for reaction between dilute hydrochloric acid and copper(II) oxide​
RSB [31]

Answer:

CuO + 2HCl = CuCl2(s) + H2O(l)

1 molecule of CuO reacts with 2 moles of HCl to form 1 mole of Copper II chloride and 1 mole of HCl

4 0
4 years ago
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