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MissTica
3 years ago
5

1. The string shown is 1.5 meters long and is vibrating as the first harmonic. The string vibrates up and down with 33 cycles in

10.0 seconds. Determine the frequency, period, wavelength and speed for this wave.
Physics
1 answer:
svet-max [94.6K]3 years ago
6 0

Answer:

Explanation:

ok

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A body in uniform velocity has zero acceleration why?
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When the velocity is uniform, the velocity does not change. since acceleration is the rate of change in velocity, the acceleration will be zero when velocity is uniform
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4 years ago
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mass of the planet is 12 times that of earth and its radius is thrice that of earth , then find the escape velocity on that plan
Over [174]

Answer:

The escape velocity on the planet is approximately 178.976 km/s

Explanation:

The escape velocity for Earth is therefore given as follows

The formula for escape velocity, v_e, for the planet is v_e = \sqrt{\dfrac{2 \cdot G \cdot m}{r} }

Where;

v_e = The escape velocity on the planet

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

m = The mass of the planet = 12 × The mass of Earth, M_E

r = The radius of the planet = 3 × The radius of Earth, R_E

The escape velocity for Earth, v_e_E, is therefore given as follows;

v_e_E = \sqrt{\dfrac{2 \cdot G \cdot M_E}{R_E} }

\therefore v_e = \sqrt{\dfrac{2 \times G \times 12 \times M}{3 \times R} } =  \sqrt{\dfrac{2 \times G \times 4 \times M}{R} } = 16 \times \sqrt{\dfrac{2 \times G \times M}{R} } = 16 \times v_e_E

v_e = 16 × v_e_E

Given that the escape velocity for Earth, v_e_E ≈ 11,186 m/s, we have;

The escape velocity on the planet = v_e ≈ 16 × 11,186 ≈ 178976 m/s ≈ 178.976 km/s.

3 0
3 years ago
If an object looses electrons, then have been transferred
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If<span> a neutral </span>object loses<span> some </span>electrons<span>, </span>then<span> it will possess more protons</span>
4 0
3 years ago
You are unloading a refrigerator from a delivery van. The ramp on the van is 5.0 mm long, and its top end is 1.4 mm above the gr
Ivahew [28]

Answer:

Work done is 1.31 J.

Explanation:

Given:

Length of the ramp (L) = 5.0 mm

Height of the top end (H) = 1.4 mm

Horizontal force applied (F) = 270 N

Work done (W) = ?

We know that,

Work done is equal to the product of force and displacement caused along the line of application of force.

Here, the force acting on the refrigerator is in the horizontal direction while the refrigerator is moving down along the length of the ramp. So, we have to first find the horizontal component of the displacement caused.

Now, consider the triangle ABC representing the given situation. The point A is the top end point of the ramp, AB is the length of the ramp, AC is the vertical displacement of the refrigerator and BC is the horizontal displacement of the refrigerator.

Using Pythagoras theorem,

AB^2=BC^2+AC^2\\\\(5.0)^2=BC^2+(1.4)^2\\\\BC=\sqrt{25.0-1.96}\\\\BC=4.86\ mm

Now, force applied on the refrigerator is in the direction opposite to the horizontal component of displacement. So, work is negative.

Work = Force × Horizontal displacement

W=270\ N\times 4.86\ mm\\\\W=1312.2\ \textrm{N-mm}\\\\W=1.31\ J\ \ \ \ \ \textrm{ [1 mm = 0.001 m]}

Therefore, work done is 1.31 J.

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3 years ago
Which type of force is used by your legs to pedal a bicycle?
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The answer is strong push. When you ride a bike, the pedals convert a vertical push from your legs into rotational motion for the wheels to turn.
8 0
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