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MissTica
3 years ago
5

1. The string shown is 1.5 meters long and is vibrating as the first harmonic. The string vibrates up and down with 33 cycles in

10.0 seconds. Determine the frequency, period, wavelength and speed for this wave.
Physics
1 answer:
svet-max [94.6K]3 years ago
6 0

Answer:

Explanation:

ok

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The charges and coordinates of two charged particles held fixed in the xy plane are: q1 = +3.3 µc, x1 = 3.5 cm, y1 = 0.50 cm, an
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1) First of all, we need to find the distance between the two charges. Their distance on the xy plane is
d= \sqrt{(x_1-x_2)^2+(y_1-y_2)^2}
substituting the coordinates of the two charges, we get
d= \sqrt{(3.5+2)^2+(0.5-1.5)^2}=5.6~cm=0.056~m

2) Then, we can calculate the electrostatic force between the two charges q_1 and q_2, which is given by
F=k_e  \frac{q_1 q_2}{d^2}
where k_e=8.99\cdot10^{9} Nm^2C^{-2} is the Coulomb's constant.
Substituting numbers, we get 
F=8.99\cdot10^{9} Nm^2C^{-2}  \frac{(3.3\cdot10^{-6}~C) (-4\cdot10^{-6}~C)}{(0.056~m)^2} =-37.8~N
and the negative sign means the force between the two charges is attractive, because the two charges have opposite sign.
7 0
3 years ago
Busco<br>n o<br><br><br><br><br>Vi<br><br><br><br><br>oookuflufurlgxbmhxmdhkhdkydkdul​
stira [4]

Answer:

Explanation:

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4 0
3 years ago
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SashulF [63]
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3 years ago
Statement A: 2.567 km, to two significant figures. Statement B: 2.567 km, to three significant figures. Determine the correct re
sammy [17]

Answer:

Statement A is greater than Statement B.

Explanation:

Statement A: 2.567 km, to two significant figures..

To 2 sig figures means only 2 whole numbers should be left after approximation. Thus, 2.567 to 2 significant figures is 2.6 km

Statement B: 2.567 km, to three significant figures. To 3 sig figures means only 3 whole numbers should be left after approximation. Thus, 2.567 to 3 significant figures is 2.57 km

Comparing both values, statement A is obviously greater than Statement B

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3 years ago
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