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Zinaida [17]
3 years ago
8

Assuming standard pressure, what physical constants are needed to calculate the change in enthalpy for raising a sample of water

from 250 K to 300 K. I) the heat capacity of ice II) the enthalpy of fusion of water III) the heat capacity of water IV) the enthalpy of vaporization of water V) the heat capacity of steam
Physics
1 answer:
Alik [6]3 years ago
8 0

Answer:

I) Heat capacity of ice (Sensible, ice), II) Enthalpy of fusion of water (Latent, fusion) and III) Heat capacity of water (Sensible, water).

Explanation:

At standard pressure, water has a fusion point and boiling point of 273.15 K and 373.15 K, respectively. Then, the total change in enthalpy is the sum of two sensible indicators and one latent indicator. That is:

\Delta H_{total} = \Delta H_{sensible, ice} + \Delta H_{latent, fusion} + \Delta H_{sensible, water}

The needed physical constants are: Heat capacity of ice (Sensible, ice), Enthalpy of fusion of water (Latent, fusion) and Heat capacity of water (Sensible, water).

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Why is acceleration of an object moving at a constant velocity always zero?
k0ka [10]

Answer:

If an object is moving with a constant velocity, then by definition it has zero acceleration. So there is no net force acting on the object. The total work done on the object is thus 0 (that's not to say that there isn't work done by individual forces on the object, but the sum is 0 ).

Explanation:

In the middle, when the object was changing position at a constant velocity, the acceleration was 0. This is because the object is no longer changing its velocity and is moving at a constant rate.

8 0
3 years ago
A baseball pitcher throws the ball in a motion where there is rotation of the forearm about the elbow joint as well as other mov
Brums [2.3K]

Answer: 330.88 J

Explanation:

Given

Linear velocity of the ball, v = 17.1 m/s

Distance from the joint, d = 0.47 m

Moment of inertia, I = 0.5 kgm²

The rotational kinetic energy, KE(rot) of an object is given by

KE(rot) = 1/2Iw²

Also, the angular velocity is given

w = v/r

Firstly, we calculate the angular velocity. Since it's needed in calculating the Kinetic Energy

w = v/r

w = 17.1 / 0.47

w = 36.38 rad/s

Now, substituting the value of w, with the already given value of I in the equation, we have

KE(rot) = 1/2Iw²

KE(rot) = 1/2 * 0.5 * 36.38²

KE(rot) = 0.25 * 1323.5

KE(rot) = 330.88 J

6 0
4 years ago
A 5.5kg radio is pushed across the table. If the acceleration is 5m/s to the right, find the net force exerted on the radio.
Sholpan [36]

Answer:

Net force exerted on the radio is 27.5 Newton.

Given:

Mass = 5.5 kg

Acceleration = 5 \frac{m}{s^{2} }

To find:

Force exerted on the radio = ?

Formula used:

F = ma

Where F = net force

m = mass

a = acceleration

Solution:

According to Newton's second law of motion,

F = ma

Where F = net force

m = mass

a = acceleration

F = 5.5 × 5

F = 27.5 Newton

Hence, Net force exerted on the radio is 27.5 Newton.


4 0
4 years ago
Which of the following is an example of an electromagnetic wave?
Gnom [1K]

light from a neon sign


3 0
3 years ago
Will an object with the density of 0.66g float?
Firdavs [7]
Yes yes it will............
6 0
3 years ago
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