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Zinaida [17]
4 years ago
8

Assuming standard pressure, what physical constants are needed to calculate the change in enthalpy for raising a sample of water

from 250 K to 300 K. I) the heat capacity of ice II) the enthalpy of fusion of water III) the heat capacity of water IV) the enthalpy of vaporization of water V) the heat capacity of steam
Physics
1 answer:
Alik [6]4 years ago
8 0

Answer:

I) Heat capacity of ice (Sensible, ice), II) Enthalpy of fusion of water (Latent, fusion) and III) Heat capacity of water (Sensible, water).

Explanation:

At standard pressure, water has a fusion point and boiling point of 273.15 K and 373.15 K, respectively. Then, the total change in enthalpy is the sum of two sensible indicators and one latent indicator. That is:

\Delta H_{total} = \Delta H_{sensible, ice} + \Delta H_{latent, fusion} + \Delta H_{sensible, water}

The needed physical constants are: Heat capacity of ice (Sensible, ice), Enthalpy of fusion of water (Latent, fusion) and Heat capacity of water (Sensible, water).

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A shopping cart with two nice kids, rolls off a horizontal roof ledge that is 50
Alisiya [41]

Answer:

9.39 m/s

Explanation:

Using the y-direction, we can solve for the time t it takes for the cart to reach the ground.

Assume the up direction is positive and the down direction is negative.

  • v₀ = 0 m/s
  • a = -9.8 m/s²
  • Δy = -50 m
  • t = ?

Find the constant acceleration equation that contains these four variables.

  • Δy = v₀t + 1/2at²  

Substitute known values into this equation.

  • -50 = (0)t + 1/2(-9.8)t²

Multiply and simplify.

  • -50 = -4.9t²

Divide both sides of the equation by -4.9.

  • 10.20408163 = t²

Square root both sides of the equation.

  • t = 3.194382825

Now we can use this time t and solve for v₀ in the x-direction. Time is most often our link between vertical and horizontal components of projectile motion.  

List out known variables in the x-direction.

  • v₀ = ?
  • t = 3.194382825 s
  • a = 0 m/s²
  • Δx = 30 m

Find the constant acceleration equation that contains these four variables.

  • Δx = v₀t + 1/2at²  

Substitute known values into the equation.

  • 30 = (v₀ · 3.194382825) + 1/2(0)(3.194382825)²

Multiply and simplify.

  • 30 = v₀ · 3.194382825

Divide both sides of the equation by 3.194382825.

  • v₀ = 9.391485505

The cart was rolling at a velocity of 9.39 m/s (initial velocity) when it left the ledge.

8 0
3 years ago
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A muscle inserts 1.5 cm from the joint axis and exerts 300 N of force at an angle of pull of 60 degrees. How much torque is prod
Amanda [17]

Answer:

torque = 3.897 N-m

Explanation:

given data

force = 300 N

angle = 60 degree

distance = 15 cm

to find out

torque

solution

we will apply here torque formula that is given below

torque = force × sinθ × distance    ...................1

put here all these value in equation 1

we get torque

torque  = force × sinθ × distance

torque  = 300 × sin60 × 1.5 ×10^{-2}

torque  = 300 × 0.8660 × 1.5 ×10^{-2}

torque  = 259.80 × 1.5 ×10^{-2}

torque  = 389.711 ×10^{-2}

torque = 3.897 N-m

8 0
3 years ago
A tuning fork produced four beats per second with a second, 270-Hz tuning fork. What are the two possible frequencies of the fir
EleoNora [17]

Answer:

frequency of the first tuning fork can be 274 Hz or 266 Hz

Explanation:

Given data :

we have number of beats per second = 4

thus, it can also be written as

Beat frequency of the tuning fork, v = 4 Hz

Frequency of the tuning fork, f = 270 Hz

now, the beat frequency is actually the difference of the consecutive frequency.

thus, we have

Frequency of the first tuning fork as = 270 Hz + 4 Hz = 274 Hz

or

Frequency of the first tuning fork as = 270 Hz - 4 Hz = 266 Hz

Therefore, the frequency of the first tuning fork can be 274 Hz or 266 Hz

7 0
3 years ago
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Vinvika [58]

Answer:

Explanation:

Given

Time taken to reach ground is t=2.7\ s

Malda initial velocity u=95\ cm/s

Let h be the height of Cliff

using h=ut+\frac{1}{2}at^2

where, u=initial velocity

t=time

In first case chirpy drop downward thus u=0

h=0+\frac{1}{2}(9.8)(2.7)^2

h=35.72\ m

For Milada there is horizontal velocity u=95 cm/s=0.95 m/s[/tex]

time taken to reach the ground will be same so distance traveled in this time with 0.95 m/s horizontal velocity is given by

R=u\times t

R=0.95\times 2.7=2.43\ m    

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