Answer:
9.39 m/s
Explanation:
Using the y-direction, we can solve for the time t it takes for the cart to reach the ground.
Assume the up direction is positive and the down direction is negative.
- v₀ = 0 m/s
- a = -9.8 m/s²
- Δy = -50 m
- t = ?
Find the constant acceleration equation that contains these four variables.
Substitute known values into this equation.
Multiply and simplify.
Divide both sides of the equation by -4.9.
Square root both sides of the equation.
Now we can use this time t and solve for v₀ in the x-direction. Time is most often our link between vertical and horizontal components of projectile motion.
List out known variables in the x-direction.
- v₀ = ?
- t = 3.194382825 s
- a = 0 m/s²
- Δx = 30 m
Find the constant acceleration equation that contains these four variables.
Substitute known values into the equation.
- 30 = (v₀ · 3.194382825) + 1/2(0)(3.194382825)²
Multiply and simplify.
Divide both sides of the equation by 3.194382825.
The cart was rolling at a velocity of 9.39 m/s (initial velocity) when it left the ledge.
Answer:
torque = 3.897 N-m
Explanation:
given data
force = 300 N
angle = 60 degree
distance = 15 cm
to find out
torque
solution
we will apply here torque formula that is given below
torque = force × sinθ × distance ...................1
put here all these value in equation 1
we get torque
torque = force × sinθ × distance
torque = 300 × sin60 × 1.5 ×
torque = 300 × 0.8660 × 1.5 ×
torque = 259.80 × 1.5 ×
torque = 389.711 ×
torque = 3.897 N-m
Answer:
frequency of the first tuning fork can be 274 Hz or 266 Hz
Explanation:
Given data :
we have number of beats per second = 4
thus, it can also be written as
Beat frequency of the tuning fork, v = 4 Hz
Frequency of the tuning fork, f = 270 Hz
now, the beat frequency is actually the difference of the consecutive frequency.
thus, we have
Frequency of the first tuning fork as = 270 Hz + 4 Hz = 274 Hz
or
Frequency of the first tuning fork as = 270 Hz - 4 Hz = 266 Hz
Therefore, the frequency of the first tuning fork can be 274 Hz or 266 Hz
Answer:
Explanation:
Given
Time taken to reach ground is 
Malda initial velocity 
Let h be the height of Cliff
using 
where, u=initial velocity
t=time
In first case chirpy drop downward thus u=0


For Milada there is horizontal velocity u=95 cm/s=0.95 m/s[/tex]
time taken to reach the ground will be same so distance traveled in this time with 0.95 m/s horizontal velocity is given by
