Answer:
vₓ = 0.566 m / s, W_total = 9.1 J
Explanation:
This exercise is a parabolic type movement, for the x axis where there is no acceleration
x = v t
vₓ = x / t
vₓ = 0.34 / 0.6
vₓ = 0.566 m / s
the work done is
X axis
In this axis there is no acceleration, therefore the sum of the forces is zero and since the work is the force times the distance, we conclude that the lock in this axis is zero.
W₁ = 0
Y axis
in this axis the force that exists is the force of gravity, that is, the weight of the body
W₂ = Fy y
W₂ = mg and
W₂ = m 9.8 0.70
W₂ = m 9.1
the work is a scalar for which we have to add the quantities obtained
W_total = W₁ + W₂
W_total = 0 + 9.1 m
W_total = 9.1 m
In order to complete the calculation, the mass of the body is needed if we assume that the mass is m = 1
W_total = 9.1 J
