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Whitepunk [10]
3 years ago
11

The magnetic north pole changes location but the geographic north pole does not true or false

Physics
1 answer:
a_sh-v [17]3 years ago
3 0
The North Magnetic Pole is the point on the surface of Earth's Northern Hemisphere at which the planet's magnetic field points vertically downwards (in other words, if a magnetic compass needle is allowed to rotate about a horizontal axis, it will point straight down). There is only one location where this occurs, near (but distinct from) the Geographic North Pole and the Geomagnetic North Pole. So yes true
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Describe two examples of how humans use electromagnetic waves.
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Electromagnetic waves are used in everyday life. You are looking at your computer screen right now. The light that is coming off of the screen is visible light, a form of electromagnetic radiation. Electromagnetic waves are also used to send information. For example, AM or FM radios are radio waves that transfer sound information to your local radio.
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A car on a roller coaster loaded with passengers has a mass of 2.0 x 10^3 kg. At the lowest point of the the track, the radius o
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Answer:

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Explanation:

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3 years ago
A vector makes an angle of 30° with the positive x-axis.
kkurt [141]

Answer:

W = 112.58 N-unit

Explanation:

Given:

- Force F = 10 N

- Angle Q of force with x axis: 30 degrees

- distance to be moved d = 13 units along + x axis

Find:

Work Done by the force F:

Solution:

The work by force in positive x direction can only be done if the both the direction of distance traveled and direction of force are parallel vectors. Hence we compute the component of Force F in x direction F_x:

                                       F_x = F*cos(Q)

                                       F_x = 10*cos(30)

                                       F_x = 8.66 N

        Hence,

                                  Work Done by force

                                        W = F_x * d

                                       W = 8.66 * 13

                                  W = 112.58 N-unit

5 0
3 years ago
Warmup: The International Space Station is orbiting with a velocity of 7,667 m/s at an altitude of 408,000 m. The radius of Eart
poizon [28]

Answer:

<u>8.671 \mathrm{m} / \mathrm{s}^{2}</u> is the centripetal acceleration.

Explanation:

As per given values  

Radius of earth (r) = 6371000 m

The "international space station" is orbiting with a velocity (v) = 7667 m/s.

"Centripetal acceleration" is the acceleration is equal to "the square of the velocity" divided by "the radius of the circular path".

\text { Centripetal acceleration a }=\frac{V^{2}}{R}

V = velocity of the orbit

R = radius of the earth + height of the space station

R = 6,371,000 + 408,000

R = 6779000 m

The direction of the centripetal acceleration is always inwards along the radius vector of the circular motion.

a=\frac{7667^{2}}{6779000}

a=\frac{58782889}{6779000}

\mathrm{a}=8.671 \mathrm{m} / \mathrm{s}^{2}

\text { The International Space Station's centripetal acceleration } 8.671 \mathrm{m} / \mathrm{s}^{2}.

5 0
3 years ago
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