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Serhud [2]
3 years ago
11

find the magnitude of the horizontal force, in N, requiered to push an object a distance of 2.00 meters in the force did 0.0430

joules of work to perform this task
Physics
2 answers:
jasenka [17]3 years ago
8 0

Answer:

.0215 n

Explanation:

olga nikolaevna [1]3 years ago
7 0
Work+Force*Distance.  Rearranging, F=W/d.  Calculating, the force must be 0.0215 N.
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Answer:

a) Tc = 750 [N]  ;b) See the explanation below.

Explanation:

To solve this problem, we first need a graphical explanation of this, as well as knowing the corresponding questions. Therefore, a search was carried out in google, in the attached image we will find a graphical description of the problem.

b)

The solution of this type of problem corresponds to the use of Newton's third law, applying static which tells us that the sum of the forces in a system in equilibrium without movement must be equal to zero.

a)

In this way we can find by means of a sum of forces on the y axis equal to zero:

- 850 - 450 + 550 + Tc = 0

Tc = 750 [N]

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3 years ago
The largest and brightest galaxies are those that contain _____.
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They contain quasars
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What will happen to the ball in example C if there is no friction?
Sloan [31]

Answer:

A) The ball will roll forever in a straight path.

8 0
3 years ago
A 4 kg bowling ball moving at 1.4 m/s east impacts a 400 g pin that is stationary. After the impact, the ball is moving at 0.5 m
nignag [31]

The speed of the pin after the elastic collision is 9 m/s east.

<h3>Final speed of the pin</h3>

The final speed of the pin is calculated by applying the principle of conservation of linear momentum as follows;

m1u1 + mu2 = m1v1 + m2v2

where;

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v2 = 3.6/0.4

v2 = 9 m/s

Thus, The speed of the pin after the elastic collision is 9 m/s east.

Learn more about linear momentum here: brainly.com/question/7538238

#SPJ1

3 0
2 years ago
11. A ball is thrown up and attains maximum height of 20 m. Calculate its initial speed. (g = 10 ms')
Archy [21]

final velocity = 0

acceleration = - 10 m/ s 2

distance. = 20 m

u = ?

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0^2 - u^ 2 = 2 * -10 * 20

-u^2 = -400

u = √ 400

u = 20m / s

5 0
3 years ago
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