Answer:
4.022 seconds and 4.99 seconds
Explanation:
Hello!
The free fall of the stone corresponds to a uniformly varied rectilinear movement
d=V_0*t+1/2*g*t^2
Being a free fall the initial speed is zero.
The distance is positive when considered in the same direction and direction as acceleration and speed.
256 feet stone
79.25 m=0 m⁄s*t+1/2*9,8 m⁄s^2 *t^2
t = 4.022 seconds
400 feet stone
121.92m=0 m⁄s*t+1/2*9,8 m⁄s^2 *t^2
t= 4,99 seconds
success with your homework!
Answer:
μ₁ = 0.1048
μ₂ = 0.1375
Explanation:
Using static equation can find in both point the moment and the forces so:
∑ M = F *d , ∑ F = 0
∑ M A = 0
N₁ * 3 - 200 * 9.81 * 1.5 = 0
N₁ = 981
∑ M y = 0
N₂ + 300 * ³/₅ - 981 - 20 * 9.81 = 0
N₂ = 997.2 N
∑ M C = 0
F₁ * 1.75 - 300 * ⁴/₅ * 0.75 = 0
F₁ = 102.86
∑ M B = 0
300 * ⁴/₅ * 1 - F₂ * 1.75 = 0
F₂ = 137.14 N
The Force F1 and F2 related the coefficients of static friction
F₁ = μ₁ * N₁ ⇒ 102.86 N = μ₁ * 981 ⇒ μ₁ = 0.1048
F₂= μ₂ * N₂ ⇒ 137.14 N = μ₂ * 997 ⇒ μ₂ = 0.1375
Here's the 'vector equation' for that situation:
(10N right) + (3N left)
= (10N right) + (-3N right)
= 7N right .
121.92 is the answer I believe
Impulse = Change in momentum.
The ball was moving with a momentum of 0.45 * 22 = 9.9
The ball comes to rest in the receivers arm; this means the ball's final velocity = 0. So mv2 = 0.45 * 0
The magnitude of the impact is just the change in momentum. 9.9 - (0.45 * 0) = 9.9
