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Answer: Decreasing the distance between Hox and Blox, increasing the mass of Hox, or increasing the mass of Hox and Blox.
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Explanation:
According to the law of universal gravitation:
Where:
is the module of the attraction force exerted between both planets
is the universal gravitation constant.
and 
are the masses of both planets.
is the distance between both planets.
As we can see, the gravity force is directly proportional to the mass of the bodies and inversely proportional to the square of the distance that separates them.
In other words:
If we decrease the distance between both planets (Hox and Blox), the gravitational pull between them will increase.
On the other hand, if we keep the distance between Hox and Blox, but we increase the mass of one of them, or increase the mass of both, the gravitational pull between them will also increase.
The kinetic energy of an object is given by:
where
K is the kinetic energy
m is the mass of the object
v is its velocity.
The comet in our problem has a mass of
and a velocity of
, so its kinetic energy is:
Answer:
Because Moon and Mars has no atmosphere.
Explanation:
Moon and Mars has no atmosphere, so there is no friction on the falling object due to the atmosphere. The speed of the falling object is more at Moon and Mars.
When a small object impact on the surface of moon or Mars with high speed, the size of crater is large than the earth as out earth has atmosphere.
Potential energy due to gravity = Ep = mgh [symbols have their usual meaning ]
Evidently, HALVING the mass will make Ep , HALF its previous value. So, It will be halved.
Answer:
A. Ahmed has a greater tangential speed than Jacques.
D. Jacques and Ahmed have the same angular speed.
Explanation:
Kinematics of the merry-go-round
The tangential speed of the merry-go-round is calculated using the following formula:
v = ω*R
Where:
v is the tangential speed in meters/second (m/s)
ω is the angular speed in radians/second (rad/s)
R is the angular speed in meters (m)
Data
dA = RA : Ahmed distance to the axis of rotation
dJ = RJ : Jacques distance to the axis of rotation
Problem development
We apply the formula (1)
v = ω*R
vA= ω*RA : Ahmed tangential speed
vJ= ω*RJ : Jacques tangential speed
Ahmed is at a greater distance from the axis of rotation than Jacques, then,
RA ˃ RJ and Ahmed and Jacques have the same speed ω, then:
vA ˃ vJ
