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3 years ago

Identify the place in the diagram where sleet forms

Chemistry

2 answers:

galina1969 [7]3 years ago

8 0

Answer:

The third box from the left hand side

Explanation:

A sleet is a form of precipitation in which water reaches the surface in a frozen state or in form of ice.

Sleets are common occurences in the temperate region.

If we trace the material circled by the third box from the origin, we would be able to provide an explanation that perfectly fits how sleets forms.

Water in the cloud is in a supersaturated frozen form. As the water encounters warm air, the freeze melts to water. As the water comes down and approaches the surface, it encounters a cold air front which immediately freezes the melt water. This is the sleet that reaches the surface.

The first and second box from the left hand side is rain droplet. The last box is snow flakes.

denpristay [2]3 years ago

8 0

Answer:The third box

Explanation:From left to right it would be rain , freezing rain , <u>sleet</u> , snow

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love history [14]

Answer:

1)There is 2.68 * 10^-11 J of energy needed

2) The nuclear binding energy for 1 mol of Ne is 1.6 *10^13 J/mol

Explanation:

Step 1: Data given

The nucleus of a21Ne atom has a amass of 20.98846 amu.

Step 2: Calculate number of protons and neutrons

The number of electrons and protons in an 21Ne atom = 10

The number of neutrons = 21 -10 =11

Step 3: mass of the atom

Mass of a proton = 1.00727647 u

Mass of a neutron = 1.0086649 u

The mass of the atom = mass of all neutrons + mass of protons

Mass of atom = 11*1.0086649 + 10*1.00727647 = 21.1680786 amu

Step 4: Calculate change of mass

The change in mass = Mass of atom - mass of neon

Δmass = 21.1680786 - 20.98846

Δmass = 0.1796186

Step 5: Calculate mass for a single nucleus

The change of mass for a single nucleus is = Δmass / number of avogadro

Δmass of nucleus = 0.1796186 / 6.022*10^23

Δmass of nucleus =2.98 * 10^-25 grams = 2.98 * 10^-28 kg

Step 6: Calculate energy to break a Ne nucleus

Calculate the amount of energy to break a Ne nucleus

ΔEnucleus = Δmass of nucleus * c²

⇒ with c = 2.9979 *10^8 m/s

ΔEnucleus = 2.98 * 10^-28 kg * (2.9979*10^8)² = 2.68 * 10^-11 J

What is the nuclear binding energy for 1 mol of Ne?

ΔE= ΔEnucleus * number of avogadro

ΔE= 2.68 * 10^-11 J * 6.022*10^23

ΔE= 1.6 *10^13 J/mol

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