Answer:
1.429 g of N₂
Explanation:
The Haber process is a reaction that combines nitrogen with hydrogen to form ammonia according to the following balanced equation:
- N₂ ₍g₎ + 3 H₂ ₍g₎ ⇆ 2NH₃ ₍g₎
One can note that 1 mol of N₂ react with H₂ to produce 2 mol of NH₃.
We cannot compare weight of a substance (in grams) to another in chemical reactions, but we can use moles, then we have to convert the weight of NH3 to moles.
no. of moles of NH₃ = (mass / molar mass) = (1.7 g / 17 g/mol) = 0.1 mol
and the actual yield is 98% , then the theoretical number of moles that would be produced are:
- percent yield = (actual yield / theoretical yield) × 100
98 = (0.1 mol / theoretical yield) × 100
theoretical no. of moles of NH₃ = (0.1 * 100) /98 = 0.102 mol
using cross multiplication
1 mol of N₂ → 2 mol of NH₃.
?? mol of N₂ → 0.102 mol of NH₃.
no of moles of N₂ = [(1 mol * 0.102 mol) / 2 mol] = 0.051 mol
Last step is to convert the moles back to grams using:
mass = (no of moles of N₂ * molar mass of N₂)
= (0.051 mol * 28 g/mol) = 1.429 g
<span>It rises confidence for the reason that the more times you conduct the similar experiment over and over should either demonstrate your hypothesis right and wrong and remove any random incidences that might touch your results. Meaning it permits to have a more accurate measure or conclusion.</span>
Volume of osmium = 1.01(0.223)(0.648) = 0.14595 cm3
Density = mass / volume
So density x volume = mass of osmium
22.6 x 0.14595 = 3.29845 g
Answer:
B
Explanation:
Temperature & pressure are directly proportional
Answer:
The equilibrium vapour pressure of a liquid is the pressure exerted by a vapour in a closed vapour and gas system which is in thermal equilibrium.
It is measured using a simple manometer
Explanation:
When liquid and vapour are in a closed container, the molecules of the liquid and vapour at a certain temperature, will attain thermal equilibrium. this means that there is no net transfer of heat between the bodies. The pressure exerted by the vapour on the liquid at this point is called the equilibrium vapour pressure.
To measure the equilibrium vapour pressure, the instrument used is a manometer. To use this, a sample of the liquid is dropped in a sealed flask connected to a manometer, and the increase in the pressure of the system is monitored as the fluid evaporates. This increase in pressure is known as the vapour pressure.
