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schepotkina [342]
2 years ago
10

Safety considerations • Sodium Hydroxide (please insert one statement of caution from MSDS)

Chemistry
1 answer:
andreev551 [17]2 years ago
6 0

Answer:

d took the test

Explanation:

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The reaction of 2-bromopropane reacts with sodium iodide in acetone is an example of Sn2 reaction.

The I - attacks from backside to give the transition state for both.

If we compare the transition state for cyclobromopropane 2-bromopropane then we see in case of cyclobromopropane transition state, one of the H is very close to the incoming I -.

This results in steric strain and less stability of the transition state. Hence 2-bromopropane reacts with sodium iodide in acetone over 104 times faster than bromocyclopropane.

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\boxed{\text{exhaust stroke}}

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\text{The cylinder releases CO$_{2}$, CO, and H$_{2}$O during the }\boxed{\textbf{exhaust stroke}}

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