Question

An object is placed at 0 on a number line. It moves 3 units to the right, then 4 units to the left, and then 6 units to the right. The displacement of the object is

Answer 1

Displacement is a vector quantity(quantity having magnitude as well direction). Adding numbers towards right of 0 and subtracting towards left of 0 you'll get, Displacement = + 3 - 4 + 6 = + 5 units. Hope this helps.

Answer 2

Answer: Displacement of the object is 5 units to the right.

Explanation: Displacement is defined as the shortest distance between the initial position and final position. It is a vector quantity because it is described by the magnitude and direction both.

The initial position O of object is 0 units.

When it moves 3 units to the right, it is at +3 position on the number line.

When it moves 4 units to the left, It is at -1 position on the number line.

Then, when it moves 6 units to the right, it is at +5 position on the number line. This is the Final Position A.

Displacement is the distance between initial point O and Final point A = 5 units to the right.

Number line is shown in the image attached.