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NemiM [27]
3 years ago
7

An object is placed at 0 on a number line. It moves 3 units to the right, then 4 units to the left, and then 6 units to the righ

t. The displacement of the object is

Chemistry
2 answers:
Irina18 [472]3 years ago
7 0
Displacement is a vector quantity(quantity having magnitude as well direction). Adding numbers towards right of 0 and subtracting towards left of 0 you'll get, Displacement = + 3 - 4 + 6 = + 5 units. Hope this helps.
nataly862011 [7]3 years ago
5 0

Answer: Displacement of the object is 5 units to the right.

Explanation: Displacement is defined as the shortest distance between the initial position and final position. It is a vector quantity because it is described by the magnitude and direction both.

The initial position O of object is 0 units.

When it moves 3 units to the right, it is at +3 position on the number line.

When it moves 4 units to the left, It is at -1 position on the number line.

Then, when it moves 6 units to the right, it is at +5 position on the number line. This is the Final Position A.

Displacement is the distance between initial point O and Final point A = 5 units to the right.

Number line is shown in the image attached.

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5. What is the systemic name for the following structure?
topjm [15]

Answer:

You are not showing the question, but I believe the answer is cis-3,4-dimethyl-3-hexene.

Explanation:

since the substituents are on same side, it call cis. Followed by the name.

5 0
3 years ago
Temperature is inversely related to the average kinetic energy of a gas.
Temka [501]
Incorrect, temperature is directly proportional to the avg. KE of a gas.
6 0
4 years ago
Starting with the stock solution of 6.0 M, how many milliliters of 6.0 M sulfuric acid are needed to make 450 mL of 1.2 M soluti
Lina20 [59]

<u>Answer:</u> The volume of stock solution needed is 90 mL

<u>Explanation:</u>

To calculate the molarity of the diluted solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the stock sulfuric acid solution

M_2\text{ and }V_2 are the molarity and volume of diluted sulfuric acid solution

We are given:

M_1=6.0M\\V_1=?mL\\M_2=1.2M\\V_2=450mL

Putting values in above equation, we get:

6.0\times V_1=1.2\times 450\\\\V_1=\frac{1.2\times 450}{6.0}=90mL

Hence, the volume of stock solution needed is 90 mL

6 0
3 years ago
A radioactive element reduces to 5.00% of its initial mass in
Stolb23 [73]

The half-life in months of a radioactive element that reduce to 5.00% of its initial mass in 500.0 years is approximately 1389 months

To solve this question, we'll begin by calculating the number of half-lives that has elapsed. This can be obtained as follow:

Amount remaining (N) = 5%

Original amount (N₀) = 100%

<h3>Number of half-lives (n) =?</h3>

N₀ × 2ⁿ = N  

5 × 2ⁿ = 100

2ⁿ = 100/5

2ⁿ = 20

Take the log of both side

Log 2ⁿ = log 20

nlog 2 = log 20

Divide both side by log 2

n = log 20 / log 2

<h3>n = 4.32</h3>

Thus, 4.32 half-lives gas elapsed.

Finally, we shall determine the half-life of the element. This can be obtained as follow.

Number of half-lives (n) = 4.32

Time (t) = 500 years

<h3>Half-life (t½) =? </h3>

t½ = t / n

t½ = 500 / 4.32

t½ = 115.74 years

Multiply by 12 to express in months

t½ = 115.74 × 12

<h3>t½ ≈ 1389 months </h3>

Therefore, the half-life of the radioactive element in months is approximately 1389 months

Learn more: brainly.com/question/24868345

8 0
3 years ago
A piston in a heat engine does 500 joules of work, and 1400 joules of heat are added to the system. Determine the change in inte
san4es73 [151]

Answer : The change in internal energy is, 900 Joules.

Solution : Given,

Heat given to the system = +1400 J

Work done by the system = -500 J

Change in internal energy is equal to the sum of heat energy and work done.

Formula used :

\Delta U=q+w

where,

\Delta U = change in internal energy

q = heat energy

w = work done

As per question, heat is added to the system that means, q is positive and work done by the system that means, w is negative.

Now put all the given values in the above formula, we get

\Delta U=(+1400J)+(-500J)=900J

Therefore, the change in internal energy is 900 J.

The change in internal energy depends on the heat energy and work done. As we will change in the heat energy and work done, then changes  will occur in the internal energy. Hence, the energy is conserved.

8 0
3 years ago
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