Separating variables, we have

Integrate both sides.


Given that
, we find

Then the particular solution is



and because
, we take the negative solution to accommodate this initial value.

Answer: 2 decimal digits
Step-by-step explanation:
When multiplying decimals, placement of the decimal point is very important. Since there is one decimal digit in each factor, there must be two decimal digits in the product. This is because tenths x tenths = hundredths
Hope this helps and good luck! :)