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1 year ago

Putting the other player's king in check is always a good move. true or false subject: chess

Mathematics

1 answer:

Elena-2011 [213]1 year ago

7 0

Putting the other player's king in check is always a good move. true

<h3>What is chess?</h3>

The policies of chess allow a king to take an opponent's piece whilst in check, so long as that piece isn't always being defended.
At the equal time, a king in the test is usually forced to move.

The standard regulations of chess, a participant may not make any pass that places or leaves their king in the test.
A player may additionally pass the king, seize the threatening piece, or block the check with some other piece.
A king cannot look at the opposing king, considering this will vicinity the first king in check as well.

Learn more about chess here:-

#SPJ2

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3 years ago

Read 2 more answers

X2 - 6x + 12 and y = 2x - 4, algebraically are

olga_2 [115]

The solution is (4, 4)

Solution:

Given system of equations are:

$y = x^2 - 6x + 12 ------ eqn\ 1\\\\y = 2x - 4 ---------- eqn\ 2$

Substitute eqn 2 in eqn 1

$x^2 - 6x + 12 = 2x - 4$

Make the right side of equation 0

$x^2 - 6x + 12 - 2x + 4 = 0\\\\x^2 -8x + 16 = 0$

Solve by quadratic equation

$\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}\\\\x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\\mathrm{For\:}\quad a=1,\:b=-8,\:c=16:\\\\x=\frac{-\left(-8\right)\pm \sqrt{\left(-8\right)^2-4\cdot \:1\cdot \:16}}{2\cdot \:1}\\\\x=\frac{-\left(-8\right)\pm \sqrt{0}}{2\cdot \:1}\\\\x = \frac{8}{2}\\\\x = 4$

Substitute x = 4 in eqn 2

y = 2(4) - 4

y = 8 - 4

y = 4

Thus solution is (4, 4)

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2 years ago

Given vector u, what is the magnitude, |u|, and directional angle, θ, in standard position?

Dominik [7]

The magnitude of a vector has to do with the vector length that is used to show the initial and final position of the vector.

<h3>What is a Vector?</h3>

This refers to the quantity that has a magnitude and direction and can be used to show position.

Hence, we can see that the vector, magnitude, and the directional angle values are not given so a general overview was given.