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JulsSmile [24]
4 years ago
5

The isomerization of methylisonitrile to acetonitrileCH3NC(g)→CH3CN(g)is first order in CH3NC . The rate constant for the reacti

on is 2.34×10−4 s−1 at 489 K .The half-life of the reaction when the initial {\rm [CH_3NC]} is 0.030 M is ________ {\rm s}.A. 1.43×105B. 3.37×10−4C. 4.28×103D. 2.14×103E. 2.96×103
Chemistry
1 answer:
lisabon 2012 [21]4 years ago
4 0

Answer:

Option E, Half life = 2.96\times 10^3\ s

Explanation:

For a first order reaction, rate constant and half-life is related as:

            t_{1/2}=\frac{0.693}{k}

Where,

t_{1/2} = Half life

k = Rate constant

Rate constant given = 2.34\times 10^{-4}\ s^{-1}

t_{1/2}=\frac{0.693}{k}

=\frac{0.693}{2.34 \times 10^{-4}}=2.96\times 10^3\ s

So, the correct option is option E.

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Answer:

3. Tails of phospholipids are hydrophobic.

Explanation:

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The phosphate head is HYDROPHILIC i.e. water-logging while the fatty acid/lipid tail is HYDROPHOBIC i.e. water-fearing. Hence, according to this question, it is TRUE that the tails of phospholipids are hydrophobic.

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3 years ago
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The volume of an ideal gas is held constant. Determine the ratio P2/P1 of the final pressure to the initial pressure when the te
cricket20 [7]

Answer:

A. P₂ / P₁ = 2

B. P₂ / P₁ = 1.1

Explanation:

A. Determination of the ratio P₂/P₁

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P₁/T₁ = P₂/T₂

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B. Determination of the ratio P₂/P₁

Volume = constant

Initial temperature (T₁) = 35.4 °C = 35.4 + 273 = 308.4 K

Final temperature (T₂) = 69.0 °C = 69 + 273 = 342 K

Final pressure /Initial pressure (P₂/P₁) =?

P₁/T₁ = P₂/T₂

P₁/308.4 = P₂/342

Cross multiply

308.4 × P₂ = P₁ × 342

Divide both side by P₁

308.4 × P₂ / P₁ = 342

Divide both side by 308.4

P₂ / P₁ = 342 / 308.4

P₂ / P₁ = 1.1

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Many enjoys the warm waters of a ______.
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Answer:

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