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2 years ago

Can someone help me out on this please having trouble on both and show work please !!

Mathematics

1 answer:

inysia [295]2 years ago

5 0

The difference of the expression is as follows:

(6y⁴ + 3y² - 7) - (12y⁴ - y² + 5) = - 6y⁴ + 4y² - 12

3(x - 5) - (2x + 4) = x - 19

<h3>How to find the difference of the expression?</h3>

The difference of the expression can be found when we combine the like terms.

Therefore,

(6y⁴ + 3y² - 7) - (12y⁴ - y² + 5)

6y⁴ + 3y² - 7 - 12y⁴ + y² - 5

6y⁴ - 12y⁴ + 3y² + y² - 7 - 5

- 6y⁴ + 4y² - 12

3(x - 5) - (2x + 4)

3x - 15 - 2x - 4

3x - 2x - 15 - 4

x - 19

learn more on expression here: brainly.com/question/14294918

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Daniel wanted to know his approximate score on the final exam for his mathematics class. His professor hinted that his score was

Marizza181 [45]

Answer:

The raw score for his exam grade is 99.69.

Step-by-step explanation:

Given : The professor announced that the mean for the class final exam was 88 with a standard deviation of 7. Given Daniel's z score of 1.67.

To find : What is the raw score for his exam grade?

Solution :

The formula use to find the z-score is

$z=\dfrac{x-\mu}{\sigma}$

Where, z=1.67 is the z-score

$\mu=88$ is the means

$\sigma=7$ is the standard deviation

x is the raw score for his exam grade

Substitute the values,

$1.67=\dfrac{x-88}{7}$

$1.67\times 7=x-88$

$11.69=x-88$

$x=88+11.69$

$x=99.69$

Therefore, the raw score for his exam grade is 99.69.

7 0

3 years ago

Can someone please help me find the simple interest

Stells [14]

$\bf ~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$300\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ t=years\dotfill &3 \end{cases} \\\\\\ I=(300)(0.04)(3)\implies I=36$