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ratelena [41]
3 years ago
9

A 500N person stands in an elevator that is moving downward at constant speed. The force that the floor exerts on the person mus

t be
A) 500N upward
B) 500N downward
C) less than 500N upwards
D) less than 500N downward
Physics
2 answers:
goldenfox [79]3 years ago
4 0

500N upward is the answer

shutvik [7]3 years ago
3 0
<h2>A) 500N upward </h2><h2>is the answer </h2>
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Compared to water, ice has a lower ____ , which allows it to float
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Compared to water, ice has a lower DENSITY, ehich allows it to float.

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A 0.080-kg remote control 22.0 cm long rests on a table, as shown in the figure below, with a length L overhanging its edge. To
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The center of gravity of a loaded truck depends on how the truck is packed. If it is 4.0 m high and 2.4 m wide, and its CG is 2.
Vitek1552 [10]

The slope of the road can be given as the ratio of the change in vertical

distance per unit change in horizontal distance.

  • The maximum steepness of the slope where the truck can be parked without tipping over is approximately <u>54.55 %</u>.

Reasons:

Width of the truck = 2.4 meters

Height of the truck = 4.0 meters

Height of the center of gravity = 2.2 meters

Required:

The allowable steepness of the slope the truck can be parked without tipping over.

Solution:

Let, <em>C</em> represent the Center of Gravity, CG

At the tipping point, the angle of elevation of the slope = θ

Where;

tan\left(\theta \right) = \dfrac{\overline{AM}}{\overline{CM}}

The steepness of the slope is therefore;

\mathrm{The \ steepness \  of  \ the  \ slope}= \dfrac{\overline{AM}}{\overline{CM}} \times 100

Where;

\overline{AM} = Half the width of the truck = \dfrac{2.4 \, m}{2} = 1.2 m

\overline{CM} = The elevation of the center of gravity above the ground = 2.2 m

\mathrm{The \ steepness \  of  \ the  \ slope}= \dfrac{1.2}{2.2} \times 100 \approx 54.55\%

tan\left(\theta \right) = \mathbf{\dfrac{2.2}{1.2}} = \dfrac{11}{6}

Elevation \ of \ the \ road \ \theta = arctan\left( \dfrac{6}{11} \right)  \approx 28.6 ^{\circ}

The maximum steepness of the slope where the truck can be parked is <u>54.55 %</u>.

Learn more here:

brainly.com/question/20793607

3 0
3 years ago
A parallel-plate capacitor is connected to a battery. What happens to the stored energy if the plate separation is doubled while
zlopas [31]

Answer:

new energy of the capacitor is half that of initial energy

Explanation:

As we know that the energy stored in the capacitor is given as

U = \frac{1}{2}CV^2

here we know that capacitance of parallel plate capacitor is given as

C = \frac{\epsilon_0 A}{d}

V = voltage of battery

so now we have capacitor remains connected to the same battery and the separation between the plates is doubled

so we have

C' = \frac{\epsilon_0 A}{2d}

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U = \frac{1}{2}(\frac{C}{2})V^2

so new energy of the capacitor is half

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The northern limit of the sun's direct rays is the?
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