Answer:
N
Explanation:
We are given that three charged particle are placed at each corner of equilateral triangle.




Side of equilateral triangle =3.3 cm=
We know that each angle of equilateral angle=
Net force=F =
Where k=
If we bisect the angle at
then we have 30 degrees from there to either charge.
Direction of vertical force due to charge
and 
Therefore, force will be added
Vertical force=
Vertical net force=
Vertical force =
Vertical force=
(towards 
Horizontal component are opposite in direction then will b subtracted
Horizontal force=
Horizontal force=
N(towards 
Net electric force acting on particle 3 due to particle =
Net force=
Net force=
N
Answer:
A. The resonator behaves as a wave guide (a hollow pipe used as a transmission line). The characteristics of the pipe depend on the type of the wave to be transmitted.
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9 is D I believe, I don't know about 10
Answer:


Explanation:
Given Data:
Numbers of times Telescope cycled around the earth in 6 years=37,000 times
Total Distance traveled in 6 years by the Hubble Space Telescope=1,280,000,000 Km
Find:
Kilometers in one Orbit=?
Solution:
Kilometers in 37,000 Orbits=1,280,000,000 Km
Kilometers in 1 Orbit=1,280,000,000/37,000
In Scientific Notation:


Kilometers in 1 Orbit=34594.594 Km
Kilometers in 1 Orbit in Scientific notation:
