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mezya [45]
3 years ago
6

What is the velocity of an object that travels 150 meters in 10 seconds?

Physics
1 answer:
natta225 [31]3 years ago
7 0

Answer:

15 m/s

Explanation:

150m ÷ 10s = 15m/s

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Batteries involve the flow of electricity from one metal to another. What happens to these metals to cause the batteries to, eve
Nataly [62]
The metals will start to rust lol. i think. because this messes up how the metals conduct the flow of the electricity.
3 0
3 years ago
5. A family of ducks is swimming in a pond at a speed of 3 m/s when a gust of wind hits them. By the time they reach the other s
ella [17]

Answer:

The time taken by the duck to cross the lake is, t= 4 s

Explanation:

Given data,

The initial speed of the ducks, u = 3 m/s

The final speed of the ducks, v = 7 m/s

The acceleration of the duck, a = 1 m/s²

The formula for the acceleration is,

                               a = (v - u) / t

∴                               t = (v - u) / a

Substituting the given values in the above equation,

                                t = (7 - 3) / 1

                                  = 4 s

Hence, the time taken by the duck to cross the lake is, t= 4 s

6 0
3 years ago
How much momentum does a 10 kg object have when is moving 30 m/s
nikklg [1K]
P = m x v

P = 30 x 10
=300
3 0
3 years ago
An object is placed perpendicular to the the principal axis of convex lens of focal length 8,the distance of the object from the
Digiron [165]

Answer:

v = 24 cm and inverted image

Explanation:

Given that,

The focal length of the object, f = +8 cm

Object distance, u = -12 cm

We need to find the position &nature of the image​. Let v be the image distance. Using lens formula to find it :

\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}

Put all the values,

\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{8}+\dfrac{1}{(-12)}\\\\v=24\ cm

So, the image distance from the lens is 24 cm.

Magnification,

m=\dfrac{v}{u}\\\\m=\dfrac{24}{-12}\\\\m=-2

The negative sign of magnification shows that the formed image is inverted.

7 0
2 years ago
A car accelerates from rest at a rate of 6.50 m/s2. Determine thevelocity of the car at t = 4.00 s.
aksik [14]

Answer:

1.62 m/s2

Explanation:

6.50 divided by 4

3 0
2 years ago
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