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2 years ago

11

True or false. The planet's speed never changes. That is why we have a stable orbit.

1 answer:

Svetradugi [14.3K]2 years ago

8 0

This answer is true the earth always stays at one speed

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An inductive argument guarantees its conclusion<br><br> True<br><br> False

lorasvet [3.4K]

Answer:

False

Explanation:

inductive arguments have some evidence but do not have full assurance of truth of the conclusion

8 0

3 years ago

Read 2 more answers

Volcanoes are formed ________. question 3 options:

blsea [12.9K]

I think the correct answer is C. Volcanoes are formed in subduction zones or in rift valleys. They are formed when hot magma within the upper mantle of the Earth would work way up the surface. As it reaches the surface, an eruption would happen forming lava flows and deposits of ash. As it continues to erupt, it would grow bigger and bigger. These would form commonly in divergence or convergence tectonic plates. On Earth, there are about 1500 volcanoes that are active. About 80 of these can be found under the oceans. The active ones are mostly found in washington, oregon, alaska, california and hawaii.

7 0

3 years ago

Learning Goal: To be able to calculate work done by a constant force directed at different angles relative to displacement

svlad2 [7]

Answer:

Woke done, W = 4156.92 Joules

Explanation:

The work done by the force can be calculated as :

$W=F\times s$

$W=Fs\ cos\theta$

$\theta$ is the angle between force and the displacement

It is assumed to find the work done for the given parameters i.e.

Force, F = 30 N

Distance travelled, s = 160 m

Angle between force and displacement, $\theta=30$

Work done is given by :

$W=Fs\ cos\theta$

$W=30\times 160\ cos(30)$

W = 4156.92 Joules

So, the work done by the object is 4156.92 Joules. Hence, this is the required solution.

5 0

3 years ago

A 26-kg sled is on a snow-covered slope. The coeﬃcients of friction between the sled’s runners and the snow are µs = 0.096 and µ

sweet-ann [11.9K]

Answer:

Explanation:

Given

mass of sled =26 kg

coefficient of static friction $\mu _s=0.096$

coefficient of kinetic friction $\mu _k=0.072$

In order to move sled from rest we need to provide a force greater than static friction which is given by

$f_s=\mu mg=0.096\times 26\times 9.8=24.46 N$

After Moving Sled kinetic friction comes in to play which is less than static friction

$f_k=\mu _kmg=0.072\times 26\times 9.8=18.34 N$

therefore minimum force to keep moving sledge at constant velocity is 18.34 N

3 0

3 years ago

A 37.9 A current flows in a long, straight wire. Find the strength of the resulting magnetic field at a distance of 45.5 cm from

Damm [24]

Answer:

$1.67\cdot 10^{-5} T$

Explanation:

The magnitude of the magnetic field produced by a current-carrying wire is given by the equation:

$B=\frac{\mu_0 I}{2\pi r}$

where:

$\mu_0=4\pi \cdot 10^{-7} H/m$ is the vaacuum permeability

I is the current in the wire

r is the distance from the wire

The direction of the magnetic field lines is tangential to concentric circles around the wire.

In this problem, we have:

$I=37.9 A$ is the current in the wire

$r=45.5 cm = 0.455 m$ is the distance from the wire

Solving for B, we find the magnitude of the magnetic field:

$B=\frac{\mu_0 I}{2\pi r}=\frac{(4\pi \cdot 10^{-7})(37.9)}{2\pi (0.455)}=1.67\cdot 10^{-5} T$

4 0

3 years ago