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2 years ago

Please help with question #2

Chemistry

1 answer:

storchak [24]2 years ago

5 0

The Ksp of the solution is 3.2 * 10^-8.

The Ksp is called the solubility product . We know it to be the equilibrium constant that shows the extent to which a substance is dissolved in solution.

Now given that;

CaF2(s) ⇔ Ca^2+(aq) + 2F^-(aq)

Ksp = [ Ca^2+] [F^-]^2

Ksp = [0.002] [0.004]^2

Ksp = 3.2 * 10^-8

Learn more about Ksp:brainly.com/question/27132799

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ANEK [815]

Answer:

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Explanation:

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3 years ago

Read 2 more answers

If you are given the molarity of a solution, what additional information would you need to find the weight/weight percent (w/w%)

Ludmilka [50]

Answer:

- The molar mass of the solute, in order to convert from moles of solute to grams of solute.

- The density of solution, to convert from volume of solution to mass of solution.

Explanation:

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In this case, since molarity is mathematically defined as the moles of solute divided by the volume of solution and the weight/weight percent as the mass of solute divided by the mass of solution, we need:

- The molar mass of the solute, in order to convert from moles of solute to grams of solute.

- The density of solution, to convert from volume of solution to mass of solution.

For instance, if a 1-M solution of HCl has a density of 1.125 g/mL, we can compute the w/w% as follows:

$w/w\%=1\frac{molHCl}{L\ sln}*\frac{36.45gHCl}{1molHCl}*\frac{1L\ sln}{1000mL\ sln}*\frac{1mL\ sln}{1.125g\ sln} *100\%\\\\w/w\%=3.15\%$

Whereas the first factor corresponds to the molar mass of HCl, the second one the conversion from L to mL of solution and the third one the density to express in terms of grams of solution.

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3 years ago

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umka21 [38]

Answer:

Explanation:

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4 years ago

A sample of vinegar was found to have an acetic acid concentration of 0.8846 m. What is the acetic acid % by mass? Assume the de

jenyasd209 [6]

Answer:

5.3%

Explanation:

Let the volume be 1 L

volume , V = 1 L

use:

number of mol,

n = Molarity * Volume

= 0.8846*1

= 0.8846 mol

Molar mass of CH3COOH,

MM = 2*MM(C) + 4*MM(H) + 2*MM(O)

= 2*12.01 + 4*1.008 + 2*16.0

= 60.052 g/mol

use:

mass of CH3COOH,

m = number of mol * molar mass

= 0.8846 mol * 60.05 g/mol

= 53.12 g

volume of solution = 1 L = 1000 mL

density of solution = 1.00 g/mL

Use:

mass of solution = density * volume

= 1.00 g/mL * 1000 mL

= 1000 g

Now use:

mass % of acetic acid = mass of acetic acid * 100 / mass of solution

= 53.12 * 100 / 1000

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4 years ago

Hydrogen containing all compounds are not acts as acids. Why?

Elodia [21]

Answer:

Explanation:

Acid = solution that split to H+ or H3O+ pH <7

The compound that can't split to H+ doesn't act as acid.

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3 years ago