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3 years ago

7

Which of the following is true for balancing equations?

1 answer:

algol [13]3 years ago

5 0

Answer:

A.

Explanation:

An equation with the equal amount and proportion of atoms of each element on both sides of the reaction is commonly referred to as a balanced chemical equation.

The law of conservation of matter asserts that no observable and empirical change in the amount of matter occurs within a conventional chemical process. As a result, each element in the product would have the same equal amount or numbers of atoms as the reactants.

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The model below shows the equation that represents how hydrogen and oxygen combine to form water. In this chemical reaction, the

Effectus [21]

Answer:

true

Explanation:

because they are balance

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2 years ago

On the cooling curve below, between points Dand Ethe substance is changing from

Irina-Kira [14]

Gas to solid ( a ) is correct i think

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3 years ago

A balloon filled with helium has a volume of 6.9 L. What is the mass, in grams, of helium in the balloon?

balandron [24]

Answer : The mass of helium gas in the balloon is, 1.23 grams.

Explanation : Given,

Volume of helium gas = 6.9 L

First we have to calculate moles of helium gas at STP.

As we know that, 1 mole of substance occupy 22.4 L volume of gas.

As, 22.4 L volume of helium gas present in 1 mole of helium

So, 6.9 L volume of helium gas present in $\frac{6.9L}{22.4L}\times 1mole=0.308mole$ of helium

Now we have to calculate the mass of helium gas.

$\text{Mass of He gas}=\text{Moles of He gas}\times \text{Molar mass of He gas}$

Molar mass of He gas = 4 g/mol

$\text{Mass of He gas}=0.308mol\times 4g/mol=1.23g$

Thus, the mass of helium gas in the balloon is, 1.23 grams.

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3 years ago

A car with a mass of 3700kg. accelerates at a rate of 8.0 m/s^2 in the backward direction. What is the net force acting on the c

Digiron [165]

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6 0

4 years ago

The room temperature electrical conductivity of a semiconductor specimen is 2.8 x 104 (?-m)-1. The electron concentration is kno

Julli [10]

Answer:

7.43 × 10²⁴ m⁻³

Explanation:

Data provided in the question:

Conductivity of a semiconductor specimen, σ = 2.8 × 10⁴ (Ω-m)⁻¹

Electron concentration, n = 2.9 × 10²² m⁻³

Electron mobility, $\mu_n$ = 0.14 m²/V-s

Hole mobility, $\mu_p$ = 0.023 m²/V-s

Now,

σ = $nq\mu_n+pq\mu_p$

or

σ = $q(n\mu_n+p\mu_p)$

here,

q is the charge on electron = 1.6 × 10⁻¹⁹ C

p is the hole density

thus,

2.8 × 10⁴ = 1.6 × 10⁻¹⁹( 2.9 × 10²² × 0.14 + p × 0.023 )

or

1.75 × 10²³ = 0.406 × 10²² + 0.023p

or

17.094 × 10²² = 0.023p

or

p = 743.217 × 10²²

or

p = 7.43 × 10²⁴ m⁻³

5 0

4 years ago