Answer:
3. rolling a sum of 20 with two standard dice
Step-by-step explanation:
If something has a probability of 0 then there is no chance of it happening
A standard die goes up to 6. The max sum you can get by rolling two dice would be 12 as 6 + 6 = 12. So you have no chance of rolling a sum of 20 with two standard dice therefore the probability would be 0.
Answer:
1.
Part A: Yes, it is (a - b)².
Part B: a² - 2ab + b² => (x - 6)² = x² - 12x + 36.
Part C: x² - 12x + 36.
2.
Part A: Not a special product.
Part B: Binomial distribution => (x + 8)(x + 1) = x² + 9x + 8.
Part C: x² + 9x + 8.
3.
Part A: Yes, it is (a + b)²
Part B: a² + 2ab + b² => (3x + 2)² = 9x² + 12x + 4.
Part C: 9x² + 12x + 4.
4.
Part A: Yes, it is (a + b)(a - b), a difference of squares.
Part B: a² - b² => 4x² - 49
Part C: 4x² - 49
5.
Part A: Not a special product.
Part B: Binomial distribution => (x - 5)(2x - 5) = 2x² - 15x + 25.
Part C: 2x² - 15x + 25
You just Said it it's 0,6666666666...
<u>Answer</u>
95,040
<u>Explanation</u>
The interpretation of this expression is; the number of permutation of 5 objects out of 12.
12P5 = 12!/(12-5)!
=12!/7!
=(12×11×10×9×8×7×6×5×4×3×2×1)/(7×6×5×4×3×2×1)
=12×11×10×9×8
=95,040
Answer:

Step-by-step explanation:
Count the number of zeros, if it's a perfect power of 10. :)