AgNO3(aq) + NaCl(aq) = AgCl(s) + NaNO3
MWt AgNO3 = 169.87; AgCl = 143.32
From the eqn 169.87 g of AgNO3 yield 143.32 g of AgCl
1.000g of AgNO3 yield 143.32/169.87 g of AgCl
Hence 4.27 g will yield (143.32/169.87)×4.27 g of AgCl
= 3.60 g of AgCl which is the theoretical yield.
% yield = (2.56/3.60)× 100 = 71.1%
A skilled chemist (e.g., Marie Curie) would get close to 100%.
Answer: 3.68 x 10^21 particles
Explanation:
Based on Avogadro's law:
1 mole of any substance has 6.02 x 10^23 atoms
Since 1 mole is the same as molar mass of a substance
237 g = 6.02 x 10^23 atoms
1.45g = Z atoms
To get the value of Z, cross multiply:
(Z atoms x 237g) = (6.02 x 10^23 atoms x 1.45g)
237Z = 8.729 x 10^23
Z = (8.729 x 10^23 / 237)
Z = 3.68 x 10^21
Thus, there are 3.68 x 10^21 representative particles in 1.45 g of the molecular compound.
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