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Vladimir [108]
3 years ago
14

What is the theoretical yield of silver chloride?

Chemistry
1 answer:
shtirl [24]3 years ago
6 0

AgNO3(aq) + NaCl(aq) = AgCl(s) + NaNO3  

MWt AgNO3 = 169.87; AgCl = 143.32  

From the eqn 169.87 g of AgNO3 yield 143.32 g of AgCl  

1.000g of AgNO3 yield 143.32/169.87 g of AgCl  

Hence 4.27 g will yield (143.32/169.87)×4.27 g of AgCl  

= 3.60 g of AgCl which is the theoretical yield.  

% yield = (2.56/3.60)× 100 = 71.1%  

A skilled chemist (e.g., Marie Curie) would get close to 100%.


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Answer:

Cp_{liquid}=2.54\frac{J}{g\°C}

Explanation:

Hello,

In this case, since silver is initially hot as it cools down, the heat it loses is gained by the liquid, which can be thermodynamically represented by:

Q_{Ag}=-Q_{liquid}

That in terms of the heat capacities, masses and temperature changes turns out:

m_{Ag}Cp_{Ag}(T_2-T_{Ag})=-m_{liquid}Cp_{liquid}(T_2-T_{liquid})

Since no phase change is happening. Thus, solving for the heat capacity of the liquid we obtain:

Cp_{liquid}=\frac{m_{Ag}Cp_{Ag}(T_2-T_{Ag})}{-m_{liquid}(T_2-T_{liquid})} \\\\Cp_{liquid}=\frac{31.2g*0.237\frac{J}{g\°C}*(28.3-227.2)\°C}{185.8g*(28.3-24.4)\°C}\\ \\Cp_{liquid}=2.54\frac{J}{g\°C}

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