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VLD [36.1K]
2 years ago
10

How many representative particles are in 1.45 g of a molecular compound with a molar mass of 237 g?

Chemistry
1 answer:
ELEN [110]2 years ago
8 0

Answer: 3.68 x 10^21 particles

Explanation:

Based on Avogadro's law:

1 mole of any substance has 6.02 x 10^23 atoms

Since 1 mole is the same as molar mass of a substance

237 g = 6.02 x 10^23 atoms

1.45g = Z atoms

To get the value of Z, cross multiply:

(Z atoms x 237g) = (6.02 x 10^23 atoms x 1.45g)

237Z = 8.729 x 10^23

Z = (8.729 x 10^23 / 237)

Z = 3.68 x 10^21

Thus, there are 3.68 x 10^21 representative particles in 1.45 g of the molecular compound.

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Titanium has five common isotopes: 46Ti (8.0%), 47Ti (7.8%), 48Ti (73.4%), 49Ti (5.5%), 50Ti (5.3%). What is the average atomic
NNADVOKAT [17]

Hey there!:

Isotopes :                          abundance :

46 Ti                                       8.0%

47 Ti                                        7.8 %

48 Ti                                      73.4 %

49 Ti                                       5.5 %

50 Ti                                         5.3 %

Weighted average =   ∑ Wa * % / 100

Therefore:

( 46 * 8.0) + (47 * 7.8 ) + (48 * 73.4 ) + ( 49 * 5.5 ) + ( 50*5.3 ) / 100 =

4792.3 / 100

= 47.923 a.m.u


       Hope that helps!

7 0
3 years ago
Consider the temperature versus time graph below. I which region is the substance in both the solid phase and the liquid phase?
SVEN [57.7K]

Answer:

2

Explanation:

The change of state occurs at a constant temperture and pressure. In the grahp we can see while the time passes, the temperature doesn't change.

The rect number 4 correspond to a liquid-gas phase

8 0
3 years ago
Read 2 more answers
A sealed flask contains 3.82 x 1024 molecules of CO, How many moles of Co, are in the flask?
Lynna [10]

Answer:

3.82 × 1024

= 3911.68

<h3>I hope this helps!</h3>
4 0
2 years ago
Read 2 more answers
Please help thank you
maxonik [38]

Answer:

K=1.7x10^{-3}

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to solve this problem by firstly setting up the equilibrium expression for the given reaction, in agreement to the law of mass action:

K=\frac{[NO]^2}{[N_2][O_2]}

Next, we plug in the given concentrations on the data table to obtain:

K=\frac{(0.034)^2}{(0.69)(0.98)}\\\\K=1.7x10^{-3}

Regards!

5 0
2 years ago
Ammonium sulfate is used as a fertilizer to supply nitrogen to crops. Write the equation for the disassociation of this compound
aksik [14]

Answer:

(NH₄)₂(SO₄)+H₂O⇒(NH₄)₂O+H₂(SO₄)

Explanation:

(NH₄)⁺(SO₄)²⁻+H₂O⇒(NH₄)⁺O²⁻+H₂(SO₄)²⁻

(NH₄)₂(SO₄)+H₂O⇒(NH₄)₂O+H₂(SO₄)

5 0
3 years ago
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