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alisha [4.7K]
3 years ago
9

if you are given one element name and % by mass, how do you find the other element in the compound? give example plz

Chemistry
1 answer:
Marta_Voda [28]3 years ago
6 0

The percentage of elements in the compound is determined from the number of elements in the compound

<h3>Further explanation  </h3>

Proust states the Comparative Law that compounds are formed from elements with the same Mass Comparison so that compounds have a fixed composition of elements

\tt \%A~in~A_xB_y=\dfrac{x\times Ar~A}{MW~A_xB_y}\times 100\%

\tt \%B~in~A_xB_y=\dfrac{y\times Ar~B}{MW~A_xB_y}\times 100\%

Example

% Lithium (Li) in Li₂CO₃(lithium carbonate)

Ar of Li = 6.941 g/mol

MW of  Li₂CO₃  = 73.891 g/mol

\tt \%Li=\dfrac{2.Ar~Li}{MW~Li_2CO_3}\times 100\%\\\\\%Li=\dfrac{2\times 6.941}{73.891}\times 100\%=18.79\%

 

 

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The only way to separate a compound into its elements is by what?
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A tank at is filled with of sulfur tetrafluoride gas and of sulfur hexafluoride gas. You can assume both gases behave as ideal g
dangina [55]

The question is incomplete, the complete question is:

A 7.00 L tank at 21.4^oC is filled with 5.43 g of sulfur hexafluoride gas and 14.2 g of sulfur tetrafluoride gas. You can assume both gases behave as ideal gases under these conditions. Calculate the mole fraction and partial pressure of each gas. Round each of your answers to significant digits.

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<u>Explanation:</u>

The number of moles is defined as the ratio of the mass of a substance to its molar mass.  The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}} ......(1)

  • <u>For sulfur hexafluoride:</u>

Given mass of sulfur hexafluoride = 5.43 g

Molar mass of sulfur hexafluoride = 146.06 g/mol

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  • <u>For sulfur tetrafluoride:</u>

Given mass of sulfur tetrafluoride = 14.2 g

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Putting values in equation 1, we get:

\text{Moles of sulfur tetrafluoride }=\frac{14.2g}{108.07g/mol}=0.1314mol

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Mole fraction is defined as the moles of a component present in the total moles of a solution. It is given by the equation:

\chi_A=\frac{n_A}{n_A+n_B} .....(2)

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Putting values in equation 2, we get:

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7 0
3 years ago
Mg(OH)2+2 HCI = MgCI2+ H2O
In-s [12.5K]

Answer:

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