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alisha [4.7K]
2 years ago
9

if you are given one element name and % by mass, how do you find the other element in the compound? give example plz

Chemistry
1 answer:
Marta_Voda [28]2 years ago
6 0

The percentage of elements in the compound is determined from the number of elements in the compound

<h3>Further explanation  </h3>

Proust states the Comparative Law that compounds are formed from elements with the same Mass Comparison so that compounds have a fixed composition of elements

\tt \%A~in~A_xB_y=\dfrac{x\times Ar~A}{MW~A_xB_y}\times 100\%

\tt \%B~in~A_xB_y=\dfrac{y\times Ar~B}{MW~A_xB_y}\times 100\%

Example

% Lithium (Li) in Li₂CO₃(lithium carbonate)

Ar of Li = 6.941 g/mol

MW of  Li₂CO₃  = 73.891 g/mol

\tt \%Li=\dfrac{2.Ar~Li}{MW~Li_2CO_3}\times 100\%\\\\\%Li=\dfrac{2\times 6.941}{73.891}\times 100\%=18.79\%

 

 

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(a) carbonate buffers are important in regulating the ph of blood at 7.40. what is the concentration ratio of co2 (usually writt
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PKa = -㏒(4.3x10^-7) = 6.37 by substitution with Pka value in the following formula:
PH = Pka + ㏒[salt/acid]
PH= PKa + ㏒[HCO3-]/[H2CO3]
㏒[HCO3-]/[H2CO3] = PH-Pka
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B) when The balanced equation for this reaction is:
H2PO42-(aq) → HPO4-(aq) + H+
and when we have Ka = 6.2x10^-8 & PH = 7.15
So Pka= -㏒Ka = -㏒(6.2x10^-8) = 7.2 by substitution by Pka value in the following formula:
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c) H3PO4(aq) ↔ H2PO-(aq) + H+
the answer is: because we have Ka =7.5x10^-3 and it is a high value of Ka to make a good buffer, also we need a week acid with th salt of the week acid as H3PO4 is a strong acid so it does'nt make a goof buffer.


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