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2 years ago

What is Kinetic Energy and Potential energy❓Ty!!

Physics

1 answer:

diamong [38]2 years ago

6 0

The energy which is possessed by an object because of its motion is called Kinetic energy.

Example:

Wind mills. Energy is formed by the motion of wind mills, so it is kinetic energy.

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The energy which is possessed by an object because of its position is called Potential energy.

Example:

A raised weight

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A wave is incident on the surface of a mirror at an angle of 41° with the normal. what can you say about its angle of reflection

Umnica [9.8K]

It's angle of reflection must be 41 degrees

we know, by the first law of reflection that angle of incidence is always equal to angle of reflection..........

7 0

3 years ago

Read 2 more answers

A 2.1 kg steel ball strikes a massive wall at 13.2 m/s at an angle of 64.8 ◦ with the perpendicular to the plane of the wall. It

solong [7]

Answer:

112 N

Explanation:

going through the question you would notice that some detail is missing, using search engines u was able to find a similar question on "https://socratic.org/questions/a-2-3-kg-steel-ball-strikes-a-wall-with-a-speed-of-8-5-m-s-at-an-angle-of-64-wit"

and here is the question i found

"A 2.3 kg steel ball strikes a wall with a speed of 8.5 m/s at an angle of 64⁰ with the surface. It bounces off with the same speed and angle. If the ball is in contact with the wall for 0.448 s. What is the average force exerted by the ball?"

you would notice that there is a change in the values from the question posted, hence we would only take the following part to complete our question, " If the ball is in contact with the wall for 0.448 s what is the average force exerted by the ball?" while retaining all original detail.

solution

mass of ball (m) = 2.1 kg

speed of ball (v) = 13.2 m/s

angle of contact (p) = 64.8°

time of contact (t) = 0.448 s

What is the average force exerted by the ball?

The average force exerted by the ball = $\frac{change in momentum}{change in time}$

where

The momentum changes only the direction perpendicular to the wall, hence the component of momentum perpendicular to the wall = m x v x sin (p) = 2.1 x 13.2 x sin 64.8 = 25.1 kg.m/s

since the ball strikes the wall and bounces off it with the same speed

and at the same angle, the component of momentum acting

perpendicular to the wall remains the same while hitting and leaving

the wall but in opposite directions.

Hence the component of momentum acting perpendicular to the wall while hitting and leaving the wall will be 25.1 kg.m/s and -25.1 kg.m/s respectively.

change in momentum = 25.1 - (-25.1) = 25.1 + 25.1 = 50.2 kg.m/s

change in time = 0.448 s

now substituting the above into the equation we have

The average force exerted by the ball = $\frac{50.2}{0.448}$ = 112 N

6 0

4 years ago

At high pressures, what two factors will cause deviations during ideal gas law calculations?

Tju [1.3M]

At high pressures, the two factors that cause deviation during ideal gas law calculation are the size of molecular and intermolecular force.

The high pressure causes the molecules to approach each other at a very close distance. In that case, if the intermolecular force of attraction is high, the molecules may undergo a state transition, which will result in a completely different outcome as predicted by Ideal gas law.

If the size of the molecule is more, that is for heavy gases like refrigerants, the ideal gas law deviates due to the fact that, with increase in pressure, the volume of gas can no longer be considered as negligible.

To know more about intermolecular force go here

brainly.com/question/9007693

#SPJ4

4 0

2 years ago

A very long uniform line of charge has charge per unit length 4.54 μC/m and lies along the x-axis. A second long uniform line of

kozerog [31]

Answer:

The magnitude of the net electric field is $6.57\times10^{5}\ N/C$

Explanation:

Given that,

Charge density $\lambda = 4.54\ \mu C/m$

Charge density $\lambda' = -2.58\ \mu C/m$

Distance $y_{1}= 0.384\ m$

Distance $y_{2}= 0.204\ m$

We need to calculate the magnitude of the net electric field

Using formula of electric field

$E=E_{1}+E_{2}$

$E=\dfrac{1}{2\pi\epsilon_{0}}(\dfrac{\lambda}{r}+\dfrac{\lambda'}{r'})$

Put the value into the formula

$E=\dfrac{1}{2\pi\times8.85\times10^{-12}}(\dfrac{4.54\times10^{-6}}{0.204}+\dfrac{2.58\times10^{-6}}{0.384-0.204})$

$E=6.57\times10^{5}\ N/C$

Hence, The magnitude of the net electric field is $6.57\times10^{5}\ N/C$

8 0

4 years ago

You toss a coin into a wishing well full of i liquid denser than the coin what will happen to the coin

Ksju [112]

If the liquid is denser than the coin, then the coin will eventually
come to rest floating, with part of it above the surface of the liquid.

That's exactly the situation if you drop the coin into mercury.

Density of copper . . . 8.96 gm/cm³
iron . . . 7.87
zinc . . . 7.13
silver . . 10.5
nickel . . .8.91
lead . . . 11.4

Density of mercury . . . 13.53 gm/cm³ !

6 0

4 years ago

What is Kinetic Energy and Potential energy❓Ty!!​

What is Kinetic Energy and Potential energy❓Ty!!