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alexandr402 [8]
3 years ago
13

A 698 kg car at rest rolls down a hill from a starting height of 7.9 m. What is the final speed of the car at the bottom of the

hill?
Physics
1 answer:
3241004551 [841]3 years ago
7 0

Answer:

Explanation:

A 698 kg car at rest rolls down a hill from a starting height of 7.9 m. What is the final speed of the car at the bottom of the hill?

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7. Imagine you are pushing a 15 kg cart full of 25 kg of bottled water up a 10o ramp. If the coefficient of friction is 0.02, wh
pentagon [3]

Answer:

The frictional force needed to overcome the cart is 4.83N

Explanation:

The frictional force can be obtained using the following formula:

F= \mu R

where \mu is the coefficient of friction = 0.02

R = Normal reaction of the load = mgcos\theta = 25 \times 9.81 \times cos 10 = 241.52N

Now that we have the necessary parameters that we can place into the equation, we can now go ahead and make our substitutions, to get the value of F.

F=0.02 \times 241.52N

F = 4.83 N

Hence, the frictional force needed to overcome the cart is 4.83N

4 0
3 years ago
A young woman with normal distant vision has a 10.0% ability to accommodate (that is, increase) the lens strength (a.k.a, lens p
Kipish [7]

Answer:

20.0 cm

Explanation:

Here is the complete question

The normal power for distant vision is 50.0 D. A young woman with normal distant vision has a 10.0% ability to accommodate (that is, increase) the power of her eyes. What is the closest object she can see clearly?

Solution

Now, the power of a lens, P = 1/f = 1/u + 1/v where f = focal length of lens, u = object distance from eye lens and v = image distance from eye lens.

Given that we require a 10 % increase in the power of the lens to accommodate the image she sees clearly, the new power P' = 50.0 D + 10/100 × 50 = 50.0 D + 5 D = 55.0 D.

Also, since the object is seen clearly, the distance from the eye lens to the retina equals the distance between the image and the eye lens. So, v = 2.00 cm = 0.02 m

Now, P' = 1/u + 1/v

1/u = P'- 1/v

1/u = 55.0 D - 1/0.02 m

1/u = 55.0 m⁻¹ - 1/0.02 m

1/u = 55.0 m⁻¹ - 50.0 m⁻¹

1/u = 5.0 m⁻¹

u = 1/5.0 m⁻¹

u = 0.2 m

u = 20 cm

So, at 55.0 dioptres, the closet object she can see is 20 cm from her eye.

8 0
2 years ago
A change in kinetic of an object is equal to the ___
podryga [215]

Answer:C..net work done on the object.

Explanation:

4 0
3 years ago
A train has a constant velocity of 2 m/s. east what is the magnitude of the horizontal acceleration of the trian?
kupik [55]

Answer:

0 m/s²

Explanation:

The velocity is constant, so there is no acceleration.

4 0
3 years ago
You are presently taking a weather observation. The sky is full of wispy cirrus clouds estimated to be about 10 km overhead. If
marshall27 [118]

Answer:

x = 2000 Km

Explanation:

Given

y = 10 km

Slope: 1 : 200

x = ?

We can apply the formula

y / x = 1 / 200   ⇒     x = 200*y = 200*10 Km

⇒     x = 2000 Km

7 0
3 years ago
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