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alexandr402 [8]
3 years ago
13

A 698 kg car at rest rolls down a hill from a starting height of 7.9 m. What is the final speed of the car at the bottom of the

hill?
Physics
1 answer:
3241004551 [841]3 years ago
7 0

Answer:

Explanation:

A 698 kg car at rest rolls down a hill from a starting height of 7.9 m. What is the final speed of the car at the bottom of the hill?

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Injury to a vein increases the risk of forming a blood clot.

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Every object that has mass attracts every other object with a gravitational force: It has been proven that the size of the
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1. Two forces act on a box as follows: F= 100 N at 02 = 170. and F2= 75 N at
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2 years ago
During a hurricane in 2008, the Westin Hotel in downtownNew Orleans suffered damage. Suppose a piece of glass dropped near the t
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Answer:

  • <u>77.8 m/s, downward</u>

Explanation:

For uniform acceleration motion, the average speed is equal to half the soum of the initial velocity, Vi, and the final velocity, Vf

  • Average speed = (Vf + Vi)/2

Also, by definition, the average speed is the distance divided by the time:

  • Average speed = distance / time

Then:

  • (Vf + Vi)/2 = 300m/6.62s

Other kinematic equation for uniform acceleration is:

  • Vf = Vi + a×t

Since the window is falling and the air resistance is ignored, a = g (gravitational acceleration ≈ 9.8m/s²)

Replacing the known values we can set a system of two equations:

From (Vf + Vi)/2 = 300m/6.62s

(Vf + Vi) = 2 × 300m/6.62s

  • Vf + Vi = 90.634      equation 1

From Vf = Vi + a×t

Vf - Vi = 9.8 (6.62)

  • Vf - Vi = 64.876     equation 2

Adding the two equations:

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2 years ago
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