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alexdok [17]
2 years ago
8

A soccer ball with a mass of 0.45 kg is rolling with a momentum of 9 kg*m/s, what is it's velocity?

Physics
1 answer:
Lelu [443]2 years ago
3 0

Answer:  20 m/s

Explanation:

P = mv

since we're trying to find the velocity, you change the formula to v = P/m

v = ?

P = 9 kgm/s

m = 0.45 kg

v = 9 kgm/s / 0.45kg  = 20 m/s

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Physics class 9 chapter 8 please tell​ please
natali 33 [55]

Answer:

(a) The motion is uniform

(b)  11.11 m/s

Explanation:

(a)

From the table below, the motion of the bus is uniform.

(b)

Speed(s) = Δd/Δt

s = Δd/Δt............. Equation 1

From the table,

Given: Δd = 10 km = 10000 m, Δt = 15 minutes = (15×60) = 900 seconds

Substitute these values into equation 1

s = 10000/900

s = 11.11 m/s

7 0
3 years ago
Two objects, each with a charge of +0.15 C are separated by a distance of 3 meters.
Mrac [35]

Answer:

A . Are the masses repelling or attracting

answer:

<em><u>So, positive energy densities ("masses") attract each other by gravitational interaction. This is the general idea.</u></em>

<em><u>B</u></em>. What is the magnitude of the electrical force between the objects<em><u>?</u></em>

<em><u>answer</u></em><em><u>:</u></em>

<em><u> </u></em><em><u>The magnitude of the electrostatic force F between two point charges q1 and q2 is directly proportional to the product of the magnitudes of charges and inversely proportional to the square of the distance between them.</u></em>

C. What would the magnitude of the force be if one of the charges was 1/3 the amount?

answer:

<em><u>0.45</u></em>

D. ) What would the force be if the distance between the charges was only 1 meter (with the original charges)?

answer;

<em><u>Fmin=2.3×10^−28</u></em><em><u>N</u></em>

<em><u>E</u></em><em><u>:</u></em><em><u> </u></em>What would the force be if one of the charges was 1/3 the amount AND the distance was 1 meter?

answer;

<em><u>Electrostatic force is directly related to the charge of each object. So if the charge of one object is doubled, then the force will become two times greater.</u></em>

<em><u>#</u></em><em><u>CARRYONLEARNING</u></em><em><u>:</u></em><em><u>)</u></em>

<em><u>LOVEUALL</u></em>

6 0
3 years ago
A woman flies 300 kilometers north, 200 kilometers west, and 500 kilometers south. How far is she from her starting point?
maria [59]
She is
\sqrt{200^2+200^2}=  ~282.84 kilometers away from her starting point
5 0
4 years ago
1) Determine the magnitude of energy for each of the blanks on the diagram. Give the correct values for 1A, 1B, and 1C.
morpeh [17]

Answer:

Explanation: y’all taking the same test as me hahahahah I got the answers but I can’t attach the picture here so hit me up on snap daniela_0789

4 0
3 years ago
The distance from earth to the center of our galaxy is about 27,000 ly (1 ly = 1 light year = 9.47 × 10^15 m), as measured by an
kompoz [17]

Answer:

The time is 1206 years.

Explanation:

Given that,

Distance = 27000 ly

1\ ly =9.47\times10^{15}\ m

Speed = 0.9990c

We need to calculate the time

Using formula of speed

v = \dfrac{d}{t}

t=\dfrac{d}{v}

Put the value into the formula

t =\dfrac{27000\times9.47\times10^{15}}{3\times10^{8}}

t=8.523\times10^{11}\ sec

We need to calculate the time dilation the clock on the spaceship

Using formula of dilation time

t'=t\sqrt{1-\dfrac{v^2}{c^2}}

t'=8.523\times10^{11}\times\sqrt{1-\dfrac{( 0.9990c)^2}{c^2}}

t'=8.523\times10^{11}\times\sqrt{1-(0.9990)^2}

t'=3.8106\times10^{10}\ sec

The time convert in years

We know that,

1\ yr= 3.16\times10^{7}\ sec

So, the time is

t'=\dfrac{3.8106\times10^{10}}{3.16\times10^{7}}

t'=1206\ years

Hence, The time is 1206 years.

8 0
3 years ago
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