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zloy xaker [14]
3 years ago
11

Consider the video tutorial you just watched. suppose that we repeat the experiment, but this time we replace the original 56-g

magnet with a more powerful magnet of the same mass. as you know from experience, the more powerful a magnet is, the more strongly it attracts or repels other magnets or magnetic objects. you have also probably noticed that magnetic forces fall off sharply with distance—two magnets that interact strongly across a distance of millimeters interact more weakly at a distance of a centimeter. (in fact, the strength of the force falls off with the square of the distance.) compared to the magnet in the video, the magnet in part a will hover at a position compared to the magnet in the video, the magnet in part a will hover at a position 1- farther above the base. 2- at the same distance above the base. 3- closer to the base.
Physics
1 answer:
Gwar [14]3 years ago
8 0

Answer:

Fm - W = 0    1) true. Imams must separate, to match the two forces, you reach equilibrium

Explanation:

When the magnet is exchanged for a stronger one, but of the same weight, the equilibrium equation

         Fm - W = 0

         Fm = W

If the weight of the imam is the same, the magnetite force must decrease, so that it will occupy the magnets must be separated a greater distance, according to the formula

          Fm = Km m ’m / r²

Where Km is value 10⁻⁷ N s²/C², r is the distance between the poles

Let's review the proposed results

1) true. Imams must separate, to match the two forces, you reach equilibrium

2) False. In this case the weight would be less than the magnetic force

3) False The magnetic force increases and equilibrium is not reached

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Answer:

a = 4.9(1 - sinθ - 0.4cosθ)

Explanation:

Really not possible without a complete setup.

I will ASSUME that this an Atwood machine with two masses (m) connected by an ideal rope passing over an ideal pulley. One mass hangs freely and the other is on a slope of angle θ to the horizontal with coefficient of friction μ. Gravity is g

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8 0
3 years ago
Which of two factors influence the weight of an object due to gravitational pull?
densk [106]
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5 0
4 years ago
A constant voltage of 12.00 V has been observed over a certain time interval across a 1.20 H inductor. The current through the i
kiruha [24]

Answer:

The time is 0.5 sec.

Explanation:

Given that,

Voltage V= 12.00 V

Inductance L= 1.20 H

Current = 3.00 A

Increases rate = 8.00 A

We need to calculate change in current

\Delta A = 8.00-3.00= 5.00\ A

We need to calculate the time interval

Using formula of inductor

V=L\dfrac{\Delta A}{\Delta t}

\Delta t =\dfrac{L\Delta A}{V}

Where, \Delta A = change in current

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\Delta t=\dfrac{1.20\times5.00}{12.00}

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4 years ago
You are sitting on a merry-go-round at a distance of 2m from its center. It spins 15 times in 3 min. What distance do you move a
soldier1979 [14.2K]

Answer:

A) 12.57 m

B) 5 RPM

C) 3.142 m/s

Explanation:

A) Distance covered in 1 Revolution:

The formula that gives the relationship between the arc length or distance covered during circular motion to the angle subtended or the revolutions, is given as follows:

s = rθ

where,

s = distance covered = ?

r = radius of circle = 2 m

θ = Angle = 2π radians  (For 1 complete Revolution)

Therefore,

s = (2 m)(2π radians)

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B) Angular Speed:

The formula for angular speed is given as:

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where,

ω = angular speed = ?

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Therefore,

ω = 15 rev/3 min

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C) Linear Speed:

The formula that gives the the linear speed of an object moving in a circular path is given as:

v = rω

where,

v = linear speed = ?

r = radius = 2 m

ω = Angular Speed in rad/s = (15 rev/min)(2π rad/1 rev)(1 min/60 s) = 1.571 rad/s

Therefore,

v = (2 m)(1.571 rad/s)

<u>v = 3.142 m/s</u>

8 0
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