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Y_Kistochka [10]
3 years ago
11

You push on a box with 100 N of force, causing it to accelerate at 5 m/s?.

Physics
2 answers:
Xelga [282]3 years ago
4 0
<h3><u>Given</u><u>:</u><u>-</u></h3>

Force,F = 100 N

Acceleration,a = 5 m/s²

<h3><u>To</u><u> </u><u>be</u><u> </u><u>calculated:-</u><u> </u></h3>

Calculate the mass of the box .

<h3><u>Formula</u><u> </u><u>used:-</u><u> </u></h3>

\bf \: Force = Mass  \times  Acceleration

<h3><u>Solution:-</u><u> </u></h3>

\sf \: Force = Mass × Acceleration

★ Substituting the values in the above formula,we get:

\sf \implies \: 100 = Mass \times 5

\sf \implies \: Mass =   \cancel\dfrac{100}{5}

\sf \implies \: Mass = 20 \: kg

Nezavi [6.7K]3 years ago
4 0

We are given with the amount of force applied and accleration of a certain body and we have to find the mass of the box.

  • Force applied = 100 N
  • Accleration = 5 m/s²

<u>According to Netwon's 2nd law,</u>

After deriving, we will get that

  • Force = Mass × Accleration

Plugging the given values to get mass,

➝ 100 N = Mass × 5 m/s²

➝ Mass = 100 / 5 kg

➝ Mass = 20 kg

Thus, the required mass of the box is 20 kg.

Carry On Learning !

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No the crate can not be pushed across the floor.

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F_{s} = \mu_{s}N

For static friction the normal force (N) is balanced by the weight of the object.

So, for the crate the static frictional force (F_{sC}) is written as

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and for the person having mass 'm' the static frictional force (F_{sP}) is written as

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