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2 years ago

PLS ANSWER FAST WILL GIVE BRAINLIEST! Use the image's labels to identify the location of each of the three subatomic particles.

Physics

1 answer:

DENIUS [597]2 years ago

5 0

Answer:

Hey

A proton(s), and neutron(s).

B electron(s).

The nucleus (A) contains TWO particles, together they are called nucleons because they are in the nucleus. The two particles in the nucleus are the proton and neutron, they are held together by the nuclear strong force.

Outside of the nucleus, the electron takes up space around the nucleons. It is held in place by the electromagnetic force. It can only be a certain distance from the nucleus as you can see (the two circles around the nucleus). It can not be in between those two distances.

Wbob1314

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Charge Q is distributed uniformly throughout the volume of an insulating sphere of radius R = 4.00 cm. At a distance of r = 8.00

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Answer:

$2.62898\times 10^{-6}\ C/m^3$

$1979.99974\ N/C$

Explanation:

k = Coulomb constant = $8.99\times 10^{9}\ Nm^2/C^2$

Q = Charge

r = Distance = 8 cm

R = Radius = 4 cm

Electric field is given by

$E=\dfrac{kQ}{r^2}\\\Rightarrow Q=\dfrac{Er^2}{k}\\\Rightarrow E=\dfrac{990\times 0.08^2}{8.99\times 10^{9}}\\\Rightarrow Q=7.04783\times 10^{-10}\ C$

Volume charge density is given by

$\sigma=\dfrac{Q}{\dfrac{4}{3}\pi R^3}\\\Rightarrow \sigma=\dfrac{7.04783\times 10^{-10}}{\dfrac{4}{3}\pi (0.04)^3}\\\Rightarrow \sigma=2.62898\times 10^{-6}\ C/m^3$

The volume charge density for the sphere is $2.62898\times 10^{-6}\ C/m^3$

$E=\dfrac{kQr}{R^3}\\\Rightarrow E=\dfrac{8.99\times 10^9\times 7.04783\times 10^{-10}\times 0.02}{0.04^3}\\\Rightarrow E=1979.99974\ N/C$

The magnitude of the electric field is $1979.99974\ N/C$

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