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3 years ago

PLS ANSWER FAST WILL GIVE BRAINLIEST! Use the image's labels to identify the location of each of the three subatomic particles.

Physics

1 answer:

DENIUS [597]3 years ago

5 0

Answer:

Hey

A proton(s), and neutron(s).

B electron(s).

The nucleus (A) contains TWO particles, together they are called nucleons because they are in the nucleus. The two particles in the nucleus are the proton and neutron, they are held together by the nuclear strong force.

Outside of the nucleus, the electron takes up space around the nucleons. It is held in place by the electromagnetic force. It can only be a certain distance from the nucleus as you can see (the two circles around the nucleus). It can not be in between those two distances.

Wbob1314

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A rock is thrown at an angle of 60∘ to the ground. If the rock lands 25m away, what was the initial speed of the rock? (Assume a

Zinaida [17]

Answer:

$v_0 = 16.82\ m/s$

Explanation:

given,

angle at which rock is thrown = 60°

rock lands at distance,d = 25 m

initial speed of rock, = ?

In horizontal direction

distance = speed x time

d = v₀ cos 60° t

25 = v₀ cos 60° t............(1)

now,

in vertical direction

displacement in vertical direction is zero

using equation of motion

$s = ut +\dfrac{1}{2}gt^2$

$0 =v_0 sin 60^0 t - 4.9 t^2$

$v_o sin 60^0 = 4.9 t$

$t = \dfrac{v_0 sin 60^0}{4.9}$

putting the value of t in equation (1)

$25 = v_0 cos 60^0\times \dfrac{v_0 sin 60^0}{4.9}$

$25 =\dfrac{v_0^2cos 60^0 sin 60^0}{4.9}$ v

$v_0^2 = 282.90$

$v_0 = 16.82\ m/s$

Hence, the initial speed of the rock is equal to 16.82 m/s

4 0

3 years ago

Can you check this? Samantha swam upstream for some distance in one hour. She then swam downstream the same river for the same d

ElenaW [278]

So her speed in still water will be 6mph :)

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3 years ago

Read 2 more answers

What do u mean by free fall?

Degger [83]

Answer:

Any motion of a body in which gravity is the sole force acting on it is known as free fall. A body in free fall has no force acting on it under general relativity, where gravity is reduced to space-time curvature.

OAmalOHpeO

7 0

3 years ago

In 1666 at the age of 23, what scientist

scoray [572]

Answer:

<h3>B - Isaac Newton</h3>

Explanation:

He first thought of his system of gravitation which he hit upon by observing an apple fall from a tree,

The incident occurring in the late summer of 1666.

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3 years ago

A non uniform rod has mass

Doss [256]

Answer:

$r_{cm} = L/3$

Explanation:

Mass: M, Length: L.

$\sigma (x) = b(L-x)$

The formula that gives center of mass is

$\vec{r}_{cm} = \frac{m_1\vec{r}_1 + m_2\vec{r}_2 + ...}{m_1 + m_2 + ...} = \frac{\Sigma m_i \vec{r}_i}{\Sigma m_i}$

In the case of a non-uniform mass density, this formula converts to

$\vec{r}_{cm} = \frac{\int\limits^L_0 {x\sigma(x)} \, dx }{\int\limits^L_0 {\sigma(x)} \, dx }$

where the denominator is the total mass and the nominator is the mass times position of each point on the rod.

We have to integrate the mass density over the total rod in order to find the total mass. Likewise, we have to integrate the center of mass of each point (xσ(x)) over the total rod. And if we divide the integrated center of mass to the total mass, we find the center of mass of the rod:

$\vec{r}_{cm} = \frac{\int\limits^L_0 {x\sigma(x)} \, dx }{\int\limits^L_0 {\sigma(x)} \, dx } = \frac{\int\limits^L_0 {xb(L-x)} \, dx }{\int\limits^L_0 {b(L-x)} \, dx } = \frac{b\int\limits^L_0{(xL - x^2)} \, dx }{b\int\limits^L_0 {(L-x)} \, dx } = \frac{\frac{x^2L}{2} - \frac{x^3}{3}}{Lx - \frac{x^2}{2}}\left \{ {{x=L} \atop {x=0}} \right.$

Here x's are cancelled. Otherwise, the denominator would be zero.

$r_{cm} = \frac{\frac{xL}{2}-\frac{x^2}{3}}{L-\frac{x}{2}}\left \{ {{x=L} \atop {x=0}} \right. = \frac{\frac{L^2}{2}-\frac{L^2}{3}}{L-\frac{L}{2}} = \frac{\frac{L^2}{6}}{\frac{L}{2}} = \frac{L}{3}$

8 0

3 years ago