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kykrilka [37]
4 years ago
12

10.88 = in scientific notation

Physics
1 answer:
rewona [7]4 years ago
8 0

Answer:

1.088x10^1

Explanation:

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A car approaches you at a constant speed, sounding its horn, and you hear a frequency of 76 Hz. After the car goes by, you hear
Talja [164]

Answer:

70.07 Hz

Explanation:

Since the sound is moving away from the observer then

f_o = f_s\frac {(v+vs)}{v} and f_o = f_s\frac {(v-vs)}{v} when moving towards observer

With f_o of 76 then taking speed in air as 343 m/s we have

76 = f_s\times\frac {(343-vs)}{343}

f_s=\frac {343\times 76}{343-v_s}

Similarly, with f_o of 65 we have

65 = f_s\times\frac {(343+vs)}{343}\\f_s=\frac {343\times 65}{343+v_s}

Now

f_s=\frac {343\times 65}{343+v_s}=\frac {343\times 76}{343-v_s}

v_s=27.76 m/s

Substituting the above into  any of the first two equations then we obtain

f_s=70.07 Hz

4 0
3 years ago
Efficincy of simple machine is 60% what does it mean?<br>​
umka2103 [35]

Explanation:

By the statement, Efficiency of a machine is 60% it is meant that 'The work output is 60% of the work input'. If you apply 100J of energy for a machine, it will be able to life load of 60 J only

7 0
3 years ago
What is not an example of absorption ?
blsea [12.9K]

-- water shooting out of a hose

-- writing an email

-- making hard-boiled eggs

-- driving to the dentist

-- the emission spectrum of a carbon arc

-- buying a new car

-- putting your shoes on

-- singing a song

-- cutting a tree down

-- learning to dance

-- cleaning the windows

-- building a radio

-- ironing your shirt

-- riding a bicycle

-- playing the piano

3 0
3 years ago
An example of a substance with a definite volume and a definite shape is
kolezko [41]
A. a steel beam. All of the rest of them change shape or volume whereas a steel beam with never change in volume or shape.
7 0
4 years ago
On the surface of the earth, weight is calculated by:
sdas [7]

On the surface of the earth, weight is calculated by multiplying mass and gravity.

 

<span>Because we know the radius of the Earth, we can use the Law of Universal Gravitation to calculate the mass of the Earth in terms of the gravitational force on an object (its weight) at the Earth's surface, using the radius of the Earth as the distance. We also need the Constant of Proportionality in the Law of Universal Gravitation, G. This value was experimentally determined by Henry Cavendish in the 18th century to be the extemely small force of 6.67 x 10</span>-11 Newtons between two objects weighing one kilogram each and separated by one meter. Cavendish determined this constant by accurately measuring the horizontal force between metal spheres in an experiment sometimes referred to as "weighing the earth."

 

 

The correct answer between all the choices given is the third choice or letter C. I am hoping that this answer has satisfied your query and it will be able to help you in your endeavor, and if you would like, feel free to ask another question.

8 0
4 years ago
Read 2 more answers
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