Answer:
a) 24 kg
b) 32 kg
Explanation:
The gauge pressure is of the gas is equal to the weight of the piston divided by its area:
p = P / A
p = m * g / (π/4 * d^2)
Rearranging
p * (π/4 * d^2) = m * g
m = p * (π/4 * d^2) / g
m = 1200 * (π/4 * 0.5^2) / 9.81 = 24 kg
After the weight is added the gauge pressure is 2.8kPa
The mass of piston plus addded weight is
m2 = 2800 * (π/4 * 0.5^2) / 9.81 = 56 kg
56 - 24 = 32 kg
The mass of the added weight is 32 kg.
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Answer:
Without Recursives
// Program is written using C++
// Comments are used for explanatory purpose
int main()
{
// Declare integer number, n
int n;
cout<<"Enter number of starts to print"
cin>>n;
// Iterate through to print * pattern
for(i=n; i>0;i--)
{
for(j=n; i>j-1;j--)
{
cout<<"*";
}
cout<"\n";
}
for(i=0; i< n; i++)
{
for(j=0;j<=i;j++)
{
cout<<"*";;
}
cout<"\n";
}
return 0;
}
Using Recursive
#include <iostream>
using namespace std;
void printStars(int lines);
int main()
{
// prompt the user to enter a number
int lines;
cin>> lines;
printStars(int lines);
return 0;
}
void printStars(int lines)
{
if (lines < 1)
return;
// to print the stars of a particular row
if (i <= lines)
{
cout << "* ";
// recursively print rest of the stars
// of the row
printPatternRecur(lines, i + 1);
}
else
{
// change line
cout << endl;
// print stars
printPatternRecur(lines-1, 1);
}
}
Answer:
Explanation:
A tension or current expressed in cosine form and with a positive sign can be converted directly into a phasor. This is done by indicating the tension and the offset angle:
So:
You can sum the phasors simply using a calculator, however, let's do it manually:
Let's find the rectangular form of each phasor using the next formulas:
For 
So:
For 
So:
Hence:
Finally:
