<img src="https://tex.z-dn.net/?f=%20%20%5Clarge%7B%5Crm%7BQuestion%3A%7D%7D" id="TexFormula1" title=" \large{\rm{Question:}}"

All categories

2 years ago

alt=" \large{\rm{Question:}}" align="absmiddle" class="latex-formula">
Give one example where the displacement is zero but the distance traveled is not zero.

Physics

1 answer:

andriy [413]2 years ago

5 0

Let us assume a man travelled from a point A to a point B over a distance 'd'. After a while he travels the same distance back to point A.

Therefore, since his initial and final positions are the same, displacement is equal to zero, and the distance travelled is (d + d) = 2d, which is not zero.

You might be interested in

Argon gas enters steadily an adiabatic turbine at 900 kPa and 450C with a velocity of 80 m/s and leaves at 150 kPa with a veloc

Crazy boy [7]

Answer:

Temperature at the exit = $267.3 C$

Explanation:

For the steady energy flow through a control volume, the power output is given as

$W_{out}= -m_{f}(h_{2}-h_{1} + \frac{v_{2}^{2}}{2} - \frac{v_{1}^{2}}{2})$

Inlet area of the turbine = $60cm^{2}= 0.006m^{2}$

To find the mass flow rate, we can apply the ideal gas laws to estimate the specific volume, from there we can get the mass flow rate.

Assuming Argon behaves as an Ideal gas, we have the specific volume $v_{1}$

$v_{1}=\frac{RT_{1}}{P_{1}}=\frac{0.2081\times723}{900}=0.1672m^{3}/kg$

$m_{f}=\frac{1}{v_{1}}\times A_{1}V_{1} = \frac{1}{0.1672}\times(0.006)(80)=2.871kg/sec$

for Ideal gasses, the enthalpy change can be calculated using the formula

$h_{2}-h_{1}=C_{p}(T_{2}-T_{1})$

hence we have

$W_{out}= -m_{f}((C_{p}(T_{2}-T_{1}) + \frac{v_{2}^{2}}{2} - \frac{v_{1}^{2}}{2})$

$250= -2.871((0.5203(T_{2}-450) + \frac{150^{2}}{2\times 1000} - \frac{80^{2}}{2\times 1000})$

<em>Note: to convert the Kinetic energy term to kilojoules, it was multiplied by 1000</em>

evaluating the above equation, we have $T_{2}=267.3C$

Hence, the temperature at the exit = $267.3 C$

5 0

3 years ago

How much tension must a rope withstand if it is used to accelerate 70.0 skier behind a boat at 1.50m/s^2?

SIZIF [17.4K]

It will be stand 46.67 all i did was divide both numbers but im not sure if im right but i hope i am hope i helped:)

6 0

3 years ago

A meter stick hurtles through space at a speed of 0. 95c relative to you, with its length perpendicular to the direction of moti

marta [7]

Answer:

Explanation:

Caty , Use the relativity formula for length. ( they teach this in H.S. ? ) it's from my Modern Physics in college, A 300 level class

L = $L_{0}$ $\sqrt{1-\frac{v^{2} }{c^{2} } }$

L = 3 $\sqrt{1-\frac{.95^{2} }{1^{2} } }$

L = 0.9367496998 meters

L = 0.94 meters approx

6 0

2 years ago

New seafloor material is formed at places in Earth’s crust where –

mr_godi [17]

Answer:

D, I think.

Explanation:

I had a quiz in Plate Tectonics and there was 2 questions that are related to this, but not the exact question.

Which material rises from cracks in oceanic crust

-molten rock

Which is the first step in the seafloor spreading process?

-a crack forms in oceanic crust.

those are all right btw, so you can decide if the answer I told you is right or not.

4 0

2 years ago

Read 2 more answers

If you swim from one point at the edge of the pool to another, along a straight line, what is the longest distance d you can swi

densk [106]

The longest distance that a person can swim is 5.64 m.

<h3>What is the longest distance?</h3>

We know that the diameter of a circle is a line that is drawn from one point to another in the circle. Now we are told that the pool is circular in nature. That implies that the longest that a person can swim could be obtained form the diameter of the circle.

Given that;

A = πr^2

A = area of teh circular pool

r = radius of the pool

r = √A/ π

r = √25/3.142

r = 2.82m

Diameter of the circular pool = 2 r = 2 (2.82 cm) = 5.64 m

Learn more about circle:brainly.com/question/11833983

#SPJ1

Missing parts;

An ad for an above-ground pool states that it is 25 m2. From the ad, you can tell that the pool is a circle. If you swim from one point at the edge of the pool to another, along a straight line, what is the longest distance d you can swim? Express your answer in three significant figures.

4 0

2 years ago