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Basile [38]
2 years ago
15

Greg is in a car at the top of a roller-coaster ride. The distance, d, of the car from the ground as the car descends is determi

ned by the equation d = 144 – 16t2, where t is the number of seconds it takes the car to travel down to each point on the ride. For which interval of time is Greg’s car moving in the air?
Physics
1 answer:
IgorLugansk [536]2 years ago
7 0
The equation d = 144 - 16 t^{2} describes the relationship of he distance traveled and the time elapsed as one object travels a specified distance. This means that when t is 2 then d is 80. You know that a car is still in the air when the distance is a positive number and zero. The equation only holds true when t is at 0 to 3. 
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Explain the relationship between magnetic fields and magnetic force.
andriy [413]

Answer:

Magnetic field is the strength of magnetism created by a magnet, whereas the magnetic force is the force due to two magnetic objects. The concepts of magnetic field and magnetic force are widely used in fields such as classical mechanics, electromagnetic theory, field theory and various other applications.

Explanation:

3 0
3 years ago
Provide an example of when momentum is conserved and explain your answer you can get 10 PTS if answered with a good explaination
dezoksy [38]

Answer:

m_1=8\ kg,\ m_2=6\ kg,\ v_1=12\ m/s, v_2=4\ m/s,\ v_1'=-6\ m/s,\ v_2'=28\ m/s

Explanation:

<u>Conservation of Momentum </u>

The total momentum of a system of two particles is

p=m_1v_1+m_2v_2

Where m1,m2,v1, and v2 are the respective masses and velocities of the particles at a given time. Then, the two particles collide and change their velocities to v1' and v2'. The final momentum is now

p'=m_1v_1'+m_2v_2'

The momentum is conserved if no external forces are acting on the system, thus

m_1v_1+m_2v_2=m_1v_1'+m_2v_2'

Let's put some numbers in the problem and say

m_1=8\ kg,\ m_2=6\ kg,\ v_1=12\ m/s, v_2=4\ m/s,\ v_1'=-6\ m/s,\ v_2'=28\ m/s

(8)(12)+(6)(4)=(8)(-6)+(6)(28)

96+24=-48+168

120=120

It means that when the particles collide, the first mass returns at 6 m/s and the second continues in the same direction at 28 m/s

4 0
3 years ago
Suppose a 1300 kg car is traveling around a circular curve in a road at a constant
Scrat [10]

Answer:

F = 4212 N

Explanation:

Given that,

Mass of a car, m = 1300 kg

Speed of car on the road is 9 m/s

Radius of curve, r = 25 m

We need to find the magnitude of the unbalanced force that steers the car out of its natural straight-  line path. The force is called centripetal force. It can be given by :

F=\dfrac{mv^2}{r}\\\\F=\dfrac{1300\times 9^2}{25}\\\\F=4212\ N

So, the force has a magnitude of 4212 N

4 0
2 years ago
PLZ HELP NOW
ZanzabumX [31]

Answer: mass x height x gravitational field strength (g)

note: gravitational field strength (g) = 10 N/Kg

55 x 15 x 10 = 8250

gpe = 8250j

Explanation:

4 0
3 years ago
Round to the hundredths place.
Ivanshal [37]

Answer:

21 protons

Explanation:

4 0
2 years ago
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