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d1i1m1o1n [39]
3 years ago
14

A car is moving 18 m/s to the east. if it takes the car 5 seconds to reach a velocity of 19 m/s to the east, what is its acceler

ation?
A. 1 m/s2 east
B. 0.2 m/s2 west
C. 0.2 m/s2 east
D. 5 m/s2 east
Physics
2 answers:
almond37 [142]3 years ago
5 0
<span>C. 0.2 m/s2 east

Hope it helps!
</span>
kakasveta [241]3 years ago
4 0
<h2>Option C is the correct answer.</h2>

Explanation:

We have equation of motion v = u + at

Initial velocity, u = 18 m/s to east

Final velocity, v = 19 m/s to east

Acceleration, a = ?

Time, t = 5 s

Substituting

             v = u + at

             19 = 18 + a x 5

              1 = 5a

               a = 0.2 m/s²

Since the velocity direction is towards east, direction of acceleration is also towards east.

So acceleration is 0.2 m/s² towards east.

Option C is the correct answer.

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Explanation:

From the question given above, the following data were obtained:

Mass (m) of box = 18 Kg

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Normal force (N) =?

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N = 18 × 9.8

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Coefficient of friction (μ) = 0.39

Normal force (N) = 176.4 N

Force of friction (F) =?

F = μN

F = 0.39 × 176.4

F = 68.796 ≈ 68.8 N

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