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d1i1m1o1n [39]
3 years ago
14

A car is moving 18 m/s to the east. if it takes the car 5 seconds to reach a velocity of 19 m/s to the east, what is its acceler

ation?
A. 1 m/s2 east
B. 0.2 m/s2 west
C. 0.2 m/s2 east
D. 5 m/s2 east
Physics
2 answers:
almond37 [142]3 years ago
5 0
<span>C. 0.2 m/s2 east

Hope it helps!
</span>
kakasveta [241]3 years ago
4 0
<h2>Option C is the correct answer.</h2>

Explanation:

We have equation of motion v = u + at

Initial velocity, u = 18 m/s to east

Final velocity, v = 19 m/s to east

Acceleration, a = ?

Time, t = 5 s

Substituting

             v = u + at

             19 = 18 + a x 5

              1 = 5a

               a = 0.2 m/s²

Since the velocity direction is towards east, direction of acceleration is also towards east.

So acceleration is 0.2 m/s² towards east.

Option C is the correct answer.

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What is the reason behind superposition?why waves behave this way?
marshall27 [118]

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Which of the following types of technologies has best helped scientists to study very high-energy objects in outer space, such a
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3 years ago
Read 2 more answers
A bungee cord can stretch, but it is never compressed. When the distance between the two ends of the cord is less than its unstr
Ksju [112]

Answer:

Explanation:

Given that

g=9.8m/s²

The spring constant is

k=50N/m

The length of the bungee cord is

Lo=32m

Height of bridge which one end of the bungee is tied is 91m

A steel ball of mass 92kg is attached to the other end of the bungee.

The potential energy(Us) of the steel ball before dropped from the bridge is given as

P.E= mgh

P.E= 92×9.8×91

P.E= 82045.6 J

Us= 82045.6 J

Potential energy)(Uc) of the cord is given as

Uc= ½ke²

Where 'e' is the extension

Then the extension is final height extended by cord minus height of cord

e=hf - hi

e=hf - 32

Uc= ½×50×(hf-32)²

Uc=25(hf-32)²

Using conservation of energy,

Then,

The potential energy of free fall equals the potential energy in string

Uc=Us

25(hf-32)²=82045.6

(hf-32)² = 82045.6/25

(hf-32)²=3281.825

Take square root of both sides

√(hf-32)²=√(3281.825)

hf-32=57.29

hf=57.29+32

hf=89.29m

We neglect the negative sign of the root because the string cannot compressed

3 0
3 years ago
The Cartesian coordinate of a point in the xy plane are (x,y)=(-3.50,-2.50)m. Find the poler coordinate of this point
Masja [62]

Answer:

The polar coordinate of P(x,y) = (-3.50\,m,-2.50\,m) is P (r,\theta) = (4.301\,m, 215.538^{\circ}).

Explanation:

Given a point in rectangular form, that is P(x,y) = (x,y), its polar form is defined by:

P(x,y) = (r,\theta) (1)

Where:

r - Norm, measured in meters.

\theta - Direction, measured in sexagesimal degrees.

The norm of the point is determined by Pythagorean Theorem:

r = \sqrt{x^{2}+y^{2}} (2)

And direction is calculated by following trigonometric relation:

\theta = \tan^{-1} \frac{y}{x} (3)

If we know that x = -3.50\,m and y = -2.50\,m, then the components of coordinates in polar form is:

r = \sqrt{(-3.50\,m)^{2}+(-2.50\,m)^{2}}

r \approx 4.301\,m

Since x < 0\,m and y < 0\,m, direction is located at 3rd Quadrant. Given that tangent function has a period of 180º, we find direction by using this formula:

\theta = 180^{\circ}+\tan^{-1} \left(\frac{-2.50\,m}{-3.50\,m} \right)

\theta \approx 215.538^{\circ}

The polar coordinate of P(x,y) = (-3.50\,m,-2.50\,m) is P (r,\theta) = (4.301\,m, 215.538^{\circ}).

5 0
3 years ago
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